9u-9t=18
original no. is 10t+u
reversed no. is 10u+t
so its (10u+t)-(10t+u)=18
which gives 9u-9t=18
* J,K,&L are coplanar
* K is the midpoint of JL
* J,K,&L are collinear
* Jk=KL
Let the points be A,B,C
#A
(leg3)
(leg1)
(leg2)
#B
We have to find perimeter



#C
The length of leg3=17.4units