Yes, because adding 50 and subtracting 50 is equal to 140+50-50.
+50-50=0
Now, you have 140+0=140.
Hope this helped☺☺
Answer:
Step-by-step explanation:
1) <u>B(1, 5)</u>
<u />
<u>Dilation</u>
(1,5) => (2x, 2y)
=> (1 x 2, 5 x 2)
=> (2, 10)
<u>Translation</u>
<u>(</u>2,10) => (x + 5, y - 3)
=> (2 + 5, 10 - 3)
=> (7, 7)
<u><em>B' = (7,7)</em></u>
2) <u>Translation</u>
(1,5) => (x + 5, y - 3)
=> (1 + 5, 5 - 3)
=> (6, 2)
<u>Dilation</u>
(6, 2) => (2x, 2y)
=> (6 x 2, 2 x 2)
=> (12, 4)
<u><em>B' = (12,4)</em></u>
Answer:
![4x^2y\sqrt[4]{3y}](https://tex.z-dn.net/?f=%204x%5E2y%5Csqrt%5B4%5D%7B3y%7D%20)
Step-by-step explanation:
![\sqrt[4]{768x^8y^5} =](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B768x%5E8y%5E5%7D%20%3D%20)
![= \sqrt[4]{256 \times 3(x^2)^4y^4y}](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B4%5D%7B256%20%5Ctimes%203%28x%5E2%29%5E4y%5E4y%7D%20)
![= \sqrt[4]{4^4 \times 3(x^2)^4y^4y}](https://tex.z-dn.net/?f=%20%3D%20%5Csqrt%5B4%5D%7B4%5E4%20%5Ctimes%203%28x%5E2%29%5E4y%5E4y%7D%20)
![= 4x^2y\sqrt[4]{3y}](https://tex.z-dn.net/?f=%20%3D%204x%5E2y%5Csqrt%5B4%5D%7B3y%7D%20)
Multiply the 2 into the ax and b, and then moving the c over and changing it's sign
hope this helps
