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Eva8 [605]
2 years ago
13

Describe a transformation or series of transformations that demonstrates the congruence between figures A and B.

Mathematics
1 answer:
N76 [4]2 years ago
5 0

Answer:

90 clockwise (or counterclockwise) rotation and then a reflection over the axis between the two shape (those two steps go in any order)

Step-by-step explanation:

for this lets mark the innermost point of each shape a (blue or A) and a' (red or B)* and the second point b and b'

here we see that the two shapes are in a position to where they seem reflected over a non-existent third diagonal axis, though this is not the case, we need to bring the shape into a position where it can be transformed to the quadrant of shape B and overlap the shape

so when you have a reflection over a diagonal axis, we can rotate or reflect the shape to a new quadrant, and perform the step thats not the first, so say we made a reflection over the X-axis, the shape is now in the lower half of the graph with shape B, from here we perform our last step wich is to rotate the shape into the quadrant of shape B in a clockwise motion, now a and a' overlap and b and b' overlap, same for c, c',d and d'

(*the ' in this case is called a prime symbol, when used, distinguishes two points or lines on a graph, A' = A prime)

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Answer:

B

explanation:

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7 0
2 years ago
?????????????????????
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8 0
2 years ago
Write the standard form of an equation of an ellipse subject to the given conditions.
irina [24]

Answer:

The answer is below

Step-by-step explanation:

The standard form of the equation of an ellipse with major axis on the y axis is given as:

\frac{(x-h)^2}{b^2} +\frac{(y-k)^2}{a^2} =1

Where (h, k) is the center of the ellipse, (h, k ± a) is the major axis, (h ± b, k) is the minor axis, (h, k ± c) is the foci and c² = a² - b²

Since the minor axis is at (37,0) and (-37,0), hence k = 0, h = 0 and b = 37

Also, the foci is at (0,5) and (0, -5), therefore c = 5

Using c² = a² - b²:

5² = a² - 37²

a² = 37² + 5² = 1369 + 25

a² = 1394

Therefore the equation of the ellipse is:

\frac{x^2}{1369}+ \frac{y^2}{1394} =1

6 0
2 years ago
What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)
zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

  • Integrals
  • Definite Integrals
  • Integration Constant C

Arc Length Formula [Parametric]:                                                                         \displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.

Interval [0, π]

<u>Step 2: Find Arc Length</u>

  1. [Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]:         \displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.
  2. Substitute in variables [Arc Length Formula - Parametric]:                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx
  3. [Integrand] Simplify:                                                                                       \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx
  4. [Integral] Evaluate:                                                                                         \displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

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