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Eva8 [605]
3 years ago
13

Describe a transformation or series of transformations that demonstrates the congruence between figures A and B.

Mathematics
1 answer:
N76 [4]3 years ago
5 0

Answer:

90 clockwise (or counterclockwise) rotation and then a reflection over the axis between the two shape (those two steps go in any order)

Step-by-step explanation:

for this lets mark the innermost point of each shape a (blue or A) and a' (red or B)* and the second point b and b'

here we see that the two shapes are in a position to where they seem reflected over a non-existent third diagonal axis, though this is not the case, we need to bring the shape into a position where it can be transformed to the quadrant of shape B and overlap the shape

so when you have a reflection over a diagonal axis, we can rotate or reflect the shape to a new quadrant, and perform the step thats not the first, so say we made a reflection over the X-axis, the shape is now in the lower half of the graph with shape B, from here we perform our last step wich is to rotate the shape into the quadrant of shape B in a clockwise motion, now a and a' overlap and b and b' overlap, same for c, c',d and d'

(*the ' in this case is called a prime symbol, when used, distinguishes two points or lines on a graph, A' = A prime)

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Charlie saves $21.45 each month for 6 months.In the seventh month, he only saves $10.60.How much money will Charlie have after 7
Tomtit [17]
$21.45 x 6 = $128.7
$128.7 + $10.60 = $139.3

Charlie will have saved $139.3 in 7 months
8 0
3 years ago
For which pair of triangles would you use AAS to prove the congruence of the 2 triangles
DerKrebs [107]

Answer:

The correct option is B.

Step-by-step explanation:

According to AAS congruence rule, two triangles are congruent if two angles and a non included side are congruent to corresponding angles and side of another triangle.

We need two angles and a non included side, to use AAS postulate.

In option A, two sides and their inclined angle are congruent, therefore these triangles are congruent by SAS postulate and option A is incorrect.

In option B, two angles and a non included side are congruent, therefore these triangles are congruent by AAS postulate and option B is correct.

In option C, two angles and their included side are congruent, therefore these triangles are congruent by ASA postulate and option C is incorrect.

In option D, all sides are congruent, therefore these triangles are congruent by SSS postulate and option D is incorrect.

8 0
3 years ago
Read 2 more answers
Jase's farm has 9 chickens, each of which laid 3 eggs. Jases farm has 4 horses. Edna's farm has chickens which laid a total of 2
s344n2d4d5 [400]

Answer:

You can use the basic multipication as an infrence



5 0
3 years ago
What is the final amount if 468 is increased by 8% followed by a further 9%
bixtya [17]

Answer:

The final amount is  550.93.

Step-by-step explanation:

Here, the given amount is 468.

Now 8% of the given amount is \frac{8}{100}  \times 468  = 37.44

⇒ 8% of 468 =  37.44

So, the New amount = Initial Amount  + 8% increase

                                  = 468. +  37.44   = 505.44

Now 9 % of the new  amount 505.44  is

[tex]\frac{9}{100}  \times 505.44  = 45.4896/tex]

⇒ 9% of 505.44  = 45.4896

So, the Final  amount = New Amount  + 9% increase

                                     =  505.44 +   45.4896   = 550.93

Hence,  final amount is  550.93.

7 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Oduvanchick [21]

Answer:

  see attached

Step-by-step explanation:

The Pythagorean theorem can be used to find the hypotenuse associated with each pair of legs. That tells you ...

  c² = a² +b² . . . . . legs a, b; hypotenuse c

__

<h3>alternate form of Pythagorean theorem</h3>

For the purpose of this problem, it is convenient to consider a slightly different form of the equation.

For legs √a and √b, the hypotenuse √c is given by ...

  (√c)² = (√a)² +(√b)²

  c = a +b

That is ...

  legs √a, √b ⇒ hypotenuse √(a+b)

__

<h3>application to this problem</h3>

Since the legs are (mostly) given in terms of square roots, the value under the radical for the hypotenuse is simply the sum of those:

legs: √1, √2 ⇒ hypotenuse √(1+2) = √3

legs: √2, √3 ⇒ hypotenuse √(2+3) = √5

legs: √5, √3 ⇒ hypotenuse √(5+3) = √8

legs: √5, √1 ⇒ hypotenuse √(5+1) = √6

_____

<em>Additional comment</em>

You may not see the leg lengths given as square roots very often. This is a rather unusual set of problems for hypotenuse length.

6 0
2 years ago
Read 2 more answers
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