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3 years ago

6

Help me solve this percentages and prices. (show your work)

1 answer:

Alona [7]3 years ago

4 0

Answer:

$34.50

$1.01

Step-by-step explanation:

For these two problems, you must find a percent of a number. Since percentages can easily be turned into decimals, this is easy to do. First, turn the percent into a decimal by moving the decimal point two to the left; so, 6.25% becomes 0.0625. Then, multiply this number by the cost, 32.47. Finally add that, 2.02, to the cost to get the final answer, $34.50. For the next question do the same. Turn the percent into a decimal and then multiply that by the cost to get the total tax, $1.01.

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What is the range of y = –3sin(x) – 4?

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Answer:

The required range of the function $y=-3\sin (x)-4$ is [-7,-1]

Step-by-step explanation:

Given : Function $y=-3\sin (x)-4$

To find : What is the range of the given function?

Solution :

The range is defined as the variation in which any function is defined.

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If a ball is thrown into the air with a velocity of 34 ft/s, its height (in feet) after t seconds is given by y = 34t − 16t2. Fi

Finger [1]

<u>ANSWER: </u>

If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second

<u>SOLUTION: </u>

Given, a ball is thrown into the air with a velocity of 34 feet per second

Initial velocity (u) = 34 feet per second

And also given a relation between displacement and time = $\mathrm{y}=34 \mathrm{t}-16 \mathrm{t}^{2}$ --- eqn 1

We need to find the velocity when t = 1 ; v = ?

We know that, v = u + at and $\mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}$

where v is instantaneous velocity and u is initial velocity

a is acceleration

t is time interval

s is displacement

using the displacement and time relation eqn (1) we get

Now, when t = 1, displacement s = 34(1) – 16(1)

$\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}=34-16$

$34 \times 1+\frac{1}{2} \times a \times 1^{2}=18$

$34+\frac{a}{2}=18$

$\begin{array}{l}{\frac{a}{2}=18-34} \\\\ {\frac{a}{2}=-16} \\ {a=-16 \times 2} \\ {a=-32}\end{array}$

here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s

now put a value in v = u + at

v = 34 + (-32)(1)

v = 34 – 32

v = 2 ft/s

Hence, velocity of the ball after 1 second is 2 ft/s

6 0

3 years ago