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3 years ago

An employee works 22 days

Mathematics

1 answer:

slega [8]3 years ago

8 0

8.25 x 22 = 181.5

181.5 divided by 60 = 3.025

each month, they would work about 3 hours

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C Betty rearranged the movies on her shelving unit after a few days. She placed equal numbers of movies on the bottom 3 shelves,

mixas84 [53]

There are total 53 movies on the shelving unit

Step-by-step explanation:

DATA

Equal movies on the bottom 3 shelves: 3x

10 movies on each of the top 2 shelves = 2*10 = 20

Equation:

3x + 20

Question:

Number of movies on the shelving unit if 11 movies are on each bottom 3 shelves: x = 11

Solution:

3x + 20

3(11) + 20 = 33 + 20 = 53

Therefore, there are total 53 movies on the shelving unit; 20 on the top 2 shelves and 33 on the bottom 3 shelves altogether.

Keywords: equation

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5 0

3 years ago

How many people choose football or soccer than baseball or basketball.

Jlenok [28]

Answers 8 football, 6 baseball and basketball, 5 soccer

Step-by-step explanation:

8 football, 6 baseball and basketball, 5 soccer

8 0

2 years ago

What is the solution to the equation-3(h+5)+2 = 4(h+6)- 9? h= 4 h= -2 h = 2 h = 4

ruslelena [56]

Expanding
-3h-15+2=4h+24-9
-3h-4h=24-9-2+15
-7h=28
h=4

8 0

3 years ago

Use the equation y=3x-8 to find y when x=8

Stels [109]

Answer: X = 8/3

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A right circular cone is undergoing a transformation in such a way that the radius of the cone is increasing at a rate of 1/2 in

Ivenika [448]

Answer:

The volume is decreasing at the rate of 1.396 cubic inches per minute

Step-by-step explanation:

Given

Shape: Cone

$\frac{dr}{dt} =\frac{1}{2}$ --- rate of the radius

$\frac{dh}{dt} =-\frac{1}{3}$ --- rate of the height

$r = 2$

$h = \frac{1}{3}$

Required

Determine the rate of change of the cone volume

The volume of a cone is:

$V = \frac{\pi}{3}r^2h$

Differentiate with respect to time (t)

$\frac{dV}{dt} = \frac{\pi}{3}(2rh \frac{dr}{dt} + r^2 \frac{dh}{dt})$

Substitute values for the known variables

$\frac{dV}{dt} = \frac{\pi}{3}(2*2*\frac{1}{3}* \frac{1}{2} - 2^2 *\frac{1}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}* \frac{1}{2} - \frac{4}{3})$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}(\frac{1}{2} - 1))$

$\frac{dV}{dt} = \frac{\pi}{3}(\frac{4}{3}*- 1)$

$\frac{dV}{dt} = -\frac{\pi}{3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{7*3}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{22}{21}*\frac{4}{3}$

$\frac{dV}{dt} = -\frac{88}{63}$

$\frac{dV}{dt} =-1.396in^3/min$

The volume is decreasing at the rate of 1.396 cubic inches per minute

3 0

3 years ago