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Usimov [2.4K]
3 years ago
11

Hiro rolls a fair pair of six-sided dice. The sample space of all possible outcomes is shown below.

Mathematics
1 answer:
Free_Kalibri [48]3 years ago
7 0

Answer: \dfrac{11}{36}

Step-by-step explanation:

Total outcomes for rolling a pair of six-sided dice n(S)= 6 x 6 =36

Let A be the event that the first die is one and B be the event that the sum of the dice is eight.

A = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)}

P(A)= =\dfrac{n(A)}{n(S)}=\dfrac{6}{36}

B= {(2,6), (6,2), (3,5), (5, 3), (4,4)}

P(B)= =\dfrac{n(B)}{n(S)}=\dfrac{5}{36}

A ∩ B = Ф

P(A ∩ B)=0

P(A or B)= P(A)+P(B)+P(A∩ B)

=\dfrac{6}{36}+\dfrac{5}{36}+0\\=\dfrac{11}{36}

Hence, P(A or B) = \dfrac{11}{36}

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Answer:

20<

Step-by-step explanation:

7 0
3 years ago
2/5 with an exponent of 3
ch4aika [34]

Answer:

2/5 with an exponent of 3 is 8/125 or 0.064

Step-by-step explanation:

Given:

A fraction = 2/5

Exponent = 3

To find the value of the fraction using the exponent.

We know that :

⇒ (a)^3=a\times a\times a  

The exponents is the number of times a number is multiplied.

So,

⇒ (\frac{2}{5})^3

⇒ \frac{2\times 2\times 2}{5\times 5\times 5}

⇒ \frac{8}{125}

On further division the number can be written as 0.064

5 0
3 years ago
A farmer wants to make a watering trough for his animals out of a cylinder. He plans to take the cylinder below and cut it in ha
Ksenya-84 [330]
V=π·r²·h
V=3.14(15²)=706.5
V=706.5x15=10597.5
V=10597.5

3 0
4 years ago
Divide (10x^3 + 19x^2 + x - 7) by (5x + 2)​
Maslowich

Answer:

2x²  +  3x  - 1   - 5/(5x +2)

Step-by-step explanation:

               2x²  +  3x  - 1  

             __________________            

  5x + 2 |   10x³ + 19x² + x - 7

             |  -<u>10x³ -   4x²  </u>

             |              15x² + x

             |            <u>- 15x² - 6x </u>  

             |                     - 5x  - 7

             |                   <u>    5x   +2</u>

             |                             - 5

2x²  +  3x  - 1   - 5/(5x +2)

6 0
3 years ago
The endpoints of `bar(EF)` are E(xE , yE) and F(xF , yF). What are the coordinates of the midpoint of `bar(EF)`?
Hoochie [10]

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are (x_{1}, y_1) and (x_2, y_2) then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})

Thus for our question the endpoints are (x_E, y_E) and (x_F, y_F) and hence the midpoint will be:

(x_M, y_M)=(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})

Thus, Option C is the correct option.

6 0
4 years ago
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