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2 years ago

12

Kevin wants to earn more than $58 trimming trees. He charges S6 per hour and pays $8 in equipment fees. What are the possible nu

mbers of hours Kevin
could trim trees?
User for the number of hours.
Write your answer as an inequality solved for t.

1 answer:

jonny [76]2 years ago

6 0

Answer:

58 ≤ 6r - 6

64 ≤ 6r

10.3 ≤ r

Step-by-step explanation:

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A factory packed 85 bears into large boxes. Each large box had 9 bears. The remaining bears were pack in small box.How many bear

zhenek [66]

The factory can pack 81 bears into 9 large boxes so 4 bears go into the small box.

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2 years ago

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

aleksandr82 [10.1K]

Hello, I Am BrotherEye

Answer:

Median = 46.5

Minimum = 32

Maximum = 62

Lower quartile = 38

Upper quartile = 59

Step-by-step explanation:

Before we can proceed to solving any of these, it is best you arrange your data first from least to greatest

32 34 37 39 41 45 48 53 58 60 61 62

First we have the median. The Median is the middle value. In this case we an even number of data, which is 12 data points. The middle value of the data would be found in between the 6th and 7th data point:

45 and 48

To get the middle value, you need to solve for the value that is in the middle of 45 and 48 by getting the sum of both numbers and dividing it by two.

45 + 48 = 93

93 ÷ 2 = 46.5

The minimum and maximum value is merely the least and greatest number.

Here we have:

Minimum = 32

Maximum = 62

To get the lower and upper quartiles, just remember that quartiles divide the data into 4 equal parts. All you need to do is find the value that is in between each quarters of the data:

Q1 (Lower) Q2(Median) Q3(Upper)

32 34 37 | 39 41 45 | 48 53 58 | 60 61 62

Like the median, we will find the value that comes in between each quarter.

Q1

37 + 39 = 76

76 ÷ 2 = 38

Lower quartile = 38

Q3:

58 + 60 = 118

118 ÷ 2 = 59

Upper quartile = 59

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2 years ago

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What is -8 * -10 / -8(-10)

Dmitry [639]

Answer:

1

Step-by-step explanation:

-8*-10/-8(-10)

80/80= 1

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3 years ago

An analogue sensor signal is sampled every 0.4ms to convert it into a digital representation. What is the corresponding sampling

kondaur [170]

<h2>Hello! It will be a pleasure to help you! </h2><h2>So let's get started:</h2><h3 /><h2>PART 1. </h2><h3>An analogue sensor signal is sampled every 0.4ms to convert it into a digital representation. What is the corresponding sampling rate?</h3>

Sampling is simply a reduction of a continuous time signal to a discrete time signal. Here we know that an analogue sensor is sampled every $0.4ms$ to convert it into a digital representation. So sampling rate, also called the sampling frequency or $f_{s}$ , is the average number of samples obtained in one second, that is, samples per second:

$f_{s}=\frac{1}{T}$

Since we know:

$T=0.4ms$

Then, the sampling rate is:

$f_{s}=\frac{1}{0.4ms} \\ \\ f_{s}=2,500 \ samples \ per \ second \\ \\ Or: \\ \\ \boxed{f_{s}=2.5kS/s}$

<h3 /><h2>PART 2. </h2><h3>According to the Sampling Theorem, for this sampling rate value, what will be the highest frequency in the digital representation, assuming the lowest frequency in the sensor signal is very close to zero.</h3><h3 />

Sampling Theorem (Nyquist Theorem) States:

<em>A </em><em>continuous time signal </em><em>can be completely represented in its samples and recovered back, if the sampling frequency </em> $f_{s}$ <em>is greater than or equal to twice frequency component of the message signal.</em>

In other words:

$f_{s}\geq 2f_{m}$

So, the highest frequency in the digital representation will be:

$f_{m}=\frac{2500}{2} \\ \\ \boxed{f_{m}=1.25kHz}$

<h2>PART 3. </h2><h3>If each sample is quantised into 2048 levels, what will be the resulting bit-rate, giving your answer in scientific notation to 2 decimal places?</h3>

Everything is Ok up to this point! But let me explain something. We do all these things in order to get a faithful reproduction of the digital signal. So the Analog-to-Digital Conversion (ADC) allows us to do that.

In this final part, each sample is quantised to 2048 levels, so this number can be written as:

$2048=2^{11}$

That is, there are $(2^{11}) \ levels$ , in other words, it takes:

$11 \ bits \ per \ sample$

Finally, the resulting bit-rate is:

$11 \times 2500 \\ \\ =27500 \ bits \ per \ second$

In scientific notation to two decimal places:

$\boxed{2.75 \times 10^4 \ bits \ per \ second}$

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3 years ago

Given: triangle XYZ, segment XY is congruent to segment ZY, and YW bisects angle XYZ. Prove that angle YWZ is a right angle.

Leya [2.2K]

Step-by-step explanation:

YW bisects the angle XYZ ------(given)

considering Δ XYZ segment XY≅YZ --------given.

∠X≅∠Z angles of opposite equal sides are equal

a triangle having two equal sides is an isosceles triangle. Isosceles triangles have one 90 degrees angles as the total sum of the three angles of a triangle must equal 180 degrees.Therefore ∠Y=90 degrees

but segment YW bisects the angle Y so ∠ZYW= 45 degrees but ∠Z=45 degrees --------(ΔXYZ is a right angled isosceles triangle)

so ∠YWZ=90 degrees as ΔYWZ is also right angled isoseles triangle having two sides equal to 45 and third = 90 degrees.

Hence segmnet YW is perpendicular on segment XZ

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3 years ago