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Solnce55 [7]
3 years ago
8

For each shape in the table, list three examples of real-world objects that could be modeled by the shape. Use your experiences,

the Internet, newspapers, magazines, or other resources to uncover examples.
Type your response here: rectangle prism -
Triangular prism -
Cylinder -
Cone -
Pyramind -
Sphere -
Mathematics
1 answer:
marishachu [46]3 years ago
5 0
Interesting question. Let's see.

Rectangular Prism: any box (like a shoe box or a  packing box).

Triangular Prism: We're not supposed to give personal answers, but I can't help it with this. When I was growing up, our front door's window had a triangular prism beveled around its edges. What made it so remarkable was that it broke up the light into a rainbow of colors on the floor. 

Cylinder. Many drinking glasses are in the shape of a cylinder. Also old fashioned water towers were cylindrical in shape.

Cone: a kitchen funnel is an upside down cone. Some funnels don't have a spout, so that makes them true cones.

Pyramid: The pyramids for the Pharaohs in Egypt.

Sphere: Any ball (beach ball, baseball basketball soccer. Some storage shapes for spices -- technically not a perfect sphere). Planets. The sun. (The earth is almost a perfect sphere).
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Bogdan [553]

9514 1404 393

Answer:

  7×10⁻¹ +6×10⁻² +5×10⁻³

Step-by-step explanation:

Place value in any place-value number system increases by a factor of the base for each place to the left of the "decimal" point. It is reduced by a factor of the base for each place to the right of the "decimal" point.

For base-10 numbers, the powers of 10 are -1, -2, -3, ... as you go to the right of the decimal point. Hence the number 0.765 decomposes as ...

  7×10⁻¹ +6×10⁻² +5×10⁻³

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Write 6,392,094,003 in word form
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Six billion three hundred ninety-two million ninety-four thousand and three
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4 years ago
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Gre4nikov [31]
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Samuel is x year old and
pogonyaev

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3 years ago
QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is
soldi70 [24.7K]

Answer:

PQR = 20

Step-by-step explanation:

Given

Bisector: QS

PQS = 5x

RQS = 2x + 6

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

PQS = RQS

Substitute expressions for PQS and RQS

5x = 2x + 6

Collect Like Terms

5x - 2x = 6

3x = 6

Divide both sides by 3

x = 2

Solving for PQR;

PQR = PQS + RQS

PQR = 5x + 2x + 6

PQR = 7x + 6

Substitute 2 for x

PQR = 7 * 2 + 6

PQR = 14 + 6

PQR = 20

4 0
4 years ago
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