The magnitude of the second atom relative to the first = 10⁻¹¹ / 10⁻¹³ = 100
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Equation</h3>
An equation is an expression used to show the relationship between two or more variables or numbers.
The magnitude of the second atom relative to the first = magnitude of second atom / magnitude of first atom
The magnitude of the second atom relative to the first = 10⁻¹¹ / 10⁻¹³ = 100
Find out more on Equation at: brainly.com/question/13763238
Answer:
$54
Step-by-step explanation:
she had 6 grandchildren and she used $9 for one grandchild so we multiply
9 x 6 = $ 54
Answer:
<em>There are approximately 114 rabbits in the year 10</em>
Step-by-step explanation:
<u>Exponential Growth
</u>
The natural growth of some magnitudes can be modeled by the equation:

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.
We are given two measurements of the population of rabbits on an island.
In year 1, there are 50 rabbits. This is the point (1,50)
In year 5, there are 72 rabbits. This is the point (5,72)
Substituting in the general model, we have:

![50=P_o(1+r)\qquad\qquad[1]](https://tex.z-dn.net/?f=50%3DP_o%281%2Br%29%5Cqquad%5Cqquad%5B1%5D)
![72=P_o(1+r)^5\qquad\qquad[2]](https://tex.z-dn.net/?f=72%3DP_o%281%2Br%29%5E5%5Cqquad%5Cqquad%5B2%5D)
Dividing [2] by [1]:

Solving for r:
![\displaystyle r=\sqrt[4]{\frac{72}{50}}-1](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B72%7D%7B50%7D%7D-1)
Calculating:
r=0.095445
From [1], solve for Po:



The model can be written now as:

In year t=10, the population of rabbits is:

P = 113.6

There are approximately 114 rabbits in the year 10
Answer:
option D: 27.5 square units
Step-by-step explanation:
Divide the polygon in 6 figures
see the attached figure
Area of figure 1 (right triangle)
A1=(1/2)(3)(3)=4.5 units²
Area of figure 2 (rectangle)
A2=(1)(3)=3 units²
Area of figure 3 (rectangle)
A3=(1)(3)=3 units²
Area of figure 4 (right triangle)
A4=(1/2)(3)(3)=4.5 units²
Area of figure 5 (right triangle)
A5=(1/2)(4)(5)=10 units²
Area of figure 6 (right triangle)
A6=(1/2)(1)(5)=2.5 units²
The total area is equal to
At=A1+A2+A3+A4+A5+A6
At=4.5+3+3+4.5+10+2.5=27.5 units²
#6 is 48 degrees and #7 is acute