For the first 60 positive integers, a = 1, n = 60, l = 60.
Sn = n/2(a + l)
s = 60/2(1 + 60) = 30(61)
For the next 60 positive integer, a = 61, n = 60, l = 120
Sum = 60/2(61 + 120) = 30(61 + 120) = 30(61) + 30(120) = s + 3600
Sum of first 120 positive integers = s + s + 3600 = 2s + 3600
Answer:
119 student tickets and 95 non-student tickets
Step-by-step explanation:
I did a trial-and-error solution.
I started with 107 students and 107 non-students:
(107*$7)+(107*$12) = $2033
It was too high, which tells us that there should be more who paid for the cheaper price.
I ended up with 119 and 95:
(119*$7)+(95*$12) = $1973
Answer:
4+7/16
Answer is 11/16
Step-by-step explanation:
Transform the expression then calculate
