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swat32
3 years ago
12

The graph Y=2(x-3)^2

Mathematics
1 answer:
Digiron [165]3 years ago
7 0
Y — 2 = ( x — 3 ) 2^
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A polynomial of degree at least 3 where all the zeros are positive whole numbers
deff fn [24]
Answer:

This is one of many possible answers.

(x -1)(x-2)(x-3)

Explanation:

The zeros are x = 1, x = 2, x = 3. This polynomial has a degree of 3.
4 0
3 years ago
19. A spherical balloon has a circumference of 19cm. what is the approximate surface area of the balloon to the nearest square c
Tamiku [17]
The main formula of a spherical surface area is SA= 4 x Pi x r²
the circumference is C= 19cm =2 Pi r, so r = C/ 2Pi = 19 / 6.28 =3.02cm
so the surface area can be found by computing
SA= 4x 3.14x 3.02² =114.5, the nearest square centimeter is <span>A) 114 cm^2</span>
5 0
3 years ago
Find the measure of angle Y
Musya8 [376]

Answer:

∠y=60°

Step-by-step explanation:

Question says to find the measure of the angle Y.

We have been given a picture of triangle XYZ. All angles are marked with same sign so that indicates that all three angles are equal.

∠x = ∠y = ∠z...(i)

We know that sum of all three angles of the triangle is always 180°.

So we can write:

∠x+∠y+∠z=180°

∠y+∠y+∠y=180°  {using equation (i) }

3∠y=180°

divide both side by 3

∠y=60°

Hence final answer is the measure of angle y is 60 degree.

8 0
4 years ago
a group of hikers begin in an elevation of -29 feet below sea level. they travel up a mountain side until they were on an elevat
katovenus [111]

Answer:

-28

Step-by-step explanation:

7 0
3 years ago
What is the number of subsets of S= {1, 2, 3…10} that contain five element include 3 or 4 but not both?
Ivenika [448]

Answer:

140

Step-by-step explanation:

To construct a subset of S with said property, we have two choices, include 3 in the subset or include four in the subset. These events are mutually exclusive because 3 and 4 can not both be elements of the subset.

First, let's count the number of subsets that contain the element 3.

Any of such subsets has five elements, but since 3 is already an element, we only have to select four elements to complete it. The four elements must be different from 3 and 4 (3 cannot be selected twice and the condition does not allow to select 4), so there are eight elements to select from. The number of ways of doing this is {}_8C_4=70.

Now, let's count the number of subsets that contain the element 4.

4 is already an element thus we have to select other four elements . The four elements must be different from 3 and 4 (4 cannot be selected twice and the condition does not allow to select 3), so there are eight elements to select from, so this can be done in {}_8C_4=70 ways.

We conclude that there are 70+70=140 required subsets of S.

7 0
3 years ago
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