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igor_vitrenko [27]
2 years ago
15

Brainliest help fast plz

Mathematics
2 answers:
Alenkasestr [34]2 years ago
8 0

Answer:

\frac{5}{16}

Step-by-step explanation:

\frac{1}{2}-\frac{3}{16}=\frac{8}{16}-\frac{3}{16}=\boxed{\frac{5}{16}}

Margaret [11]2 years ago
5 0

Answer:

hope this helps

Step-by-step explanation:

the answer is 5/16

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andrey2020 [161]

Answer:

-26

Step-by-step explanation:

2+2−(5)(6)=

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3 years ago
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(6z²+z-1)(9z-5) polynomial equation
olasank [31]
Hi there, (6z²+z-1)(9z-5)=(6z²+z+-1)(9z+-5)=(6z²)(9z)+(6z²)(-5)+(z)(9z)+(z)(-5)+(-1)(9z)+(-1)(-5)=54z³-30z²+9z²-5z-9z+5=54z³-21z²-14z+5. Therefore, the answer is 54z³-21z²-14z+5.
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Work out<br> 2/21<br> +<br> 6/7<br> Give your answer in its simplest form.
olganol [36]

Answer:

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Step-by-step explanation:

2/21+6/7

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4 0
2 years ago
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I need helpppppppppppp
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you start at the origin and go down 4 right 1. So the range is 4 and the domain is x

Step-by-step explanation:

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3 years ago
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Plz help me plz I need answer and explanation plz
pentagon [3]

9514 1404 393

Answer:

  A = {put, the, cake, in, basket}

  B = {is, the, cake, in, basket}

  C = {no, the, cake, in, basket}

  D = { }

Step-by-step explanation:

A = (A -B) ∪ (A∩B) ∪ (A∩C}

A = {put} ∪ {the, cake, in, basket} ∪ {the, cake, in, basket}

A = {put, the, cake, in, basket}

__

B = (B -A) ∪ (B -C) ∪ (B∩A) ∪ (B∩C)

B = {is} ∪ {is} ∪ {the, cake, in, basket} ∪ {the, cake, in, basket}

B = {is, the, cake, in, basket}

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C = (C -B) ∪ (C∩A) ∪ (C∩B)

C = {no} ∪ {the, cake, in, basket} ∪ {the, cake, in, basket}

C = {no, the, cake, in, basket}

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D = { } . . . . not defined anywhere

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3 years ago
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