Answer:
Bro im stuck on the same question
Step-by-step explanation:
The answer to the question is d
You made a mistake with the probability
, which should be
in the last expression, so to be clear I will state the expression again.
So we want to solve the following:
Conditioned on this event, show that the probability that her paper is in drawer
, is given by:
(1)
and
(2) ![\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.](https://tex.z-dn.net/?f=%5Cfrac%7Bp_%7Bi%7D%20%281-d_%7Bi%7D%20%29%7D%7B1-d_%7Bi%7Dp_%7Bi%7D%20%20%7D%20%2C%20if%20j%20%3D%20i.)
so we can say:
is the event that you search drawer
and find nothing,
is the event that you search drawer
and find the paper,
is the event that the paper is in drawer ![k, k = 1, ..., n.](https://tex.z-dn.net/?f=k%2C%20k%20%3D%201%2C%20...%2C%20n.)
this gives us:
![P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}](https://tex.z-dn.net/?f=P%28B%29%20%3D%20P%28B%20%5Ccap%20C_%7Bi%7D%20%29%20%3D%20P%28C_%7Bi%7D%29P%28B%20%7C%20C_%7Bi%7D%20%29%20%3D%20d_%7Bi%7D%20p_%7Bi%7D)
![P(A) = 1 - P(B) = 1 - d_{i} p_{i}](https://tex.z-dn.net/?f=P%28A%29%20%3D%201%20-%20P%28B%29%20%3D%201%20-%20d_%7Bi%7D%20p_%7Bi%7D)
Solution to Part (1):
if
, then
,
this means that
![P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }](https://tex.z-dn.net/?f=P%28C_%7Bj%7D%20%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20C_%7Bj%7D%29%7D%7BP%28A%29%7D%20%20%3D%20%5Cfrac%7BP%28C_%7Bj%7D%20%29%7D%7BP%28A%29%7D%20%20%3D%20%5Cfrac%7Bp_%7Bj%7D%20%7D%7B1-d_%7Bi%7Dp_%7Bi%7D%20%20%7D)
as needed so part one is solved.
Solution to Part(2):
so we have now that if
=
, we get that:
![P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}](https://tex.z-dn.net/?f=P%28C_%7Bj%7D%7CA%20%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20C_%7Bj%7D%29%7D%7BP%28A%29%7D)
remember that:
![P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}](https://tex.z-dn.net/?f=P%28A%7CC_%7Bj%7D%20%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20C_%7Bj%7D%29%7D%7BP%28C_%7Bj%7D%29%7D)
this implies that:
![P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )](https://tex.z-dn.net/?f=P%28A%20%5Ccap%20C_%7Bj%7D%29%20%3D%20P%28C_%7Bj%7D%29%20%5Ccdot%20P%28A%7CC_%7Bj%7D%29%20%3D%20p_%7Bi%7D%20%281-d_%7Bi%7D%20%29)
so we just need to combine the above relations to get:
![P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }](https://tex.z-dn.net/?f=P%28C_%7Bj%7D%7CA%29%20%3D%20%5Cfrac%7Bp_%7Bi%7D%20%281-d_%7Bi%7D%20%29%7D%7B1-d_%7Bi%7Dp_%7Bi%7D%20%20%7D)
as needed so part two is solved.
3 by 10kg? ioooooooooooooo
Answer:
62.7
Step-by-step explanation:
165 * 0.38 = 62.7
This is assuming you mean an object weights 38% less on mars then earth, if its the other way around(they weight 38% more on mars then earth) it would be,
165 * 1.38 = 227.7