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Delvig [45]
3 years ago
12

12÷3+(4×2)= 300×152÷(12×3)= 1988-1911= 2021-(16×2)=

Mathematics
2 answers:
daser333 [38]3 years ago
7 0

Answer:

12, 1266.66 , 77 & 1989.

Step-by-step explanation:

12÷3+(4x2)= 12

300 x 152÷(12x3)= 1266.66

1988-1911= 77

2021-(16x2)= 1989

vaieri [72.5K]3 years ago
5 0

Answer:

a)12

b)1297.8( not sure for this)

c)77

d)1989

Step-by-step explanation:

12÷3+(4×2)

12÷3+8

4+8

12.

309×152÷(12×3)

309×152÷36

309×4.2

1297.8.

1988-1911

77

2021-(16×2)

2021-32

1989

if it helps don't forget to like and Mark me

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Coffee: A popular chain of cafes has been receiving online complaints about one store location. Regular customers complained tha
spin [16.1K]

Answer:

z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67  

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=18 represent the ounce cups of coffee that were underfilled

\hat p=\frac{18}{100}=0.18 estimated proportion of ounce cups of coffee that were underfilled

p_o=0.1 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion it's higher than 0.1 or 10%:  

Null hypothesis:p\leq 0.1  

Alternative hypothesis:p > 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed for this case is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a one right tailed test the p value would be:  

p_v =P(Z>2.67)=0.0037  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance thetrue proportion is not significanlty higher than 0.1 or 10% .  

5 0
4 years ago
Flights arriving to DTW might be national or international. Assume that one out of every five national flights is followed by an
Dvinal [7]

Answer:

1/15

Step-by-step explanation:

Given

1 out of every 5 national flight is followed by an international flight.

p = 1/5

q = 1 - p

q = 1 - 1/5

q = 4/5

π0 = 0.25

We want to determine

p:the fraction of international flights that are followed by a national flight.

Let X = 0

If the nth flight is national

Let X = 1

if the flight is international

This gives rise to a two state Markov chain with transition probability as follows

P = (4/5. 1/5. p. 1-p)

The long run proportion are the below solution gotten from the Markov chain above

π0 = 4/5π0 + pπ1 ----- 1

π1 = 1/5π0 + (1 - p)π1---- 2

π0 + π1 = 1 -----------. 3

Solving the above equations,

We have

Substitute 0.25 for π0 in (3)

0.25 + π1 = 1

π1 = 1 - 0.25

π1 = 0.75

Solving 1 and 3

Substitute 0.75 for π1 and 0.25 for π0 in (1)

0.25 = 4/5 * 0.25 + 0.75p

0.25 = 0.2 + 0.75p

0.75p = 0.25 - 0.2

0.75p = 0.05

p = 0.05/0.75

P = 1/15 or 0.0667(6.67%)

So, one out of every 15 international flights is followed by a national flight (or 6.66 percent)

3 0
3 years ago
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LekaFEV [45]

Answer:

x= -0.94 repeating

Step-by-step explanation:

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4 0
3 years ago
Students in an engineering class designed model airplanes. The average distance flown was 48 feet. The table shows the differenc
Svetradugi [14.3K]

Answer:

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
chet counts balloons for a party counts 13 bunches of balloons each bunch has 5.how many balloons does chet count.
Hoochie [10]

65 balloons are counted by Chet

<u>Solution: </u>

Given that  

Chet counts balloons for a party

Number of bunches of balloons counted by Chet = 13

Also each bunch has 5 balloons.  

Need to calculated how much balloons is counted by Chet

Number of balloons in 1 bunch = 5

Number of balloons in 13 bunches = 13 x Number of balloons in 1 bunch = 13 x 5 = 65

As number of bunches of balloons counted by Chet = 13

So number of bunches of balloons counted by Chet = Number of balloons in 13 bunches = 65

Hence 65 balloons are counted by Chet.

6 0
3 years ago
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