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VashaNatasha [74]
3 years ago
13

What is the distance from (4, -4) to (-7, -8)

Mathematics
2 answers:
Soloha48 [4]3 years ago
8 0

Answer: 5

Step-by-step explanation:

use distance formula for these types of equations x1-x2 squared plus y1 -y2 squared. add both sides together square them and then get a total and then square your total for the answer. In this case 5

shtirl [24]3 years ago
4 0

the distance from (4,-4) to (-7,-8) is 11.70

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Mark has a container that looks like a cube. He uses 64 cubes with side lengths of 1 inch to completely fill the container. what
sp2606 [1]

Answer:

4 inches. if the volume is 64, then the length, width, and height are all 4 inches. 4 x 4 x 4 = 64. hope this helps

Step-by-step explanation:

- Zombie

5 0
2 years ago
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2.32x10 to the fifth power
laiz [17]
2.32 x 10⁵ = 232000

This can be solved by multiplying 2.32 to the product of 10 multiplied 5 times.

10⁵ = 10 * 10 * 10 * 10 *10
10⁵ = 100,000

2.32 x 100000 = 232000

The given equation is the standard form of a decimal number. It is used to write down a very large or very small number easily.

There are a lot of standard forms. Like: Standard form of an equation and Standard form of a polynomial.


3 0
3 years ago
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WORTH 100 POINTS!
zzz [600]

Answer:

7miles

equations shown in work image below

work shown on the paper with more explanations because text is hard to write equations (sorry I used km but it is miles for your problem.)

:) please give a heart for thanks

and brainliest crown :)

Step-by-step explanation:

For both d=r*t

Each bikes to others house and leave at the same time so for Tony,

11 = 30*t

t= 11/30 hours

for Gerry,

11 = 25*t

t= 11/25 hours

Comparing these, with LCD,

Tony's time is 55/150

Gerry's time is 66/150

So Tony got to Gerry's house 11/150 hours quicker than Gerry got to Tony's house.

Now they turn around and head back toward each other. If they leave at the same exact time, the elapsed time for each until they met would be the same so t (for tony) = t (for gerry), but Tony got a head start.

We start the stopwatch when Gerry turns around 11/150 hours after Tony has turned around. If Gerry's time to where they meet from Tony's house t(gerry), then Tony's time from Gerry's house is t(gerry) + 11/150

5 0
3 years ago
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What is the first step in solving the equation x2 – 16/25 = 0?
Keith_Richards [23]

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                     x^2-(16/25)=0 

Step by step solution :<span>Step  1  :</span> 16 Simplify —— 25 <span>Equation at the end of step  1  :</span><span><span> 16 (x2) - —— = 0 25 </span><span> Step  2  :</span></span>Rewriting the whole as an Equivalent Fraction :

<span> 2.1 </span>  Subtracting a fraction from a whole 

Rewrite the whole as a fraction using <span> 25 </span> as the denominator :

<span> x2 x2 • 25 x2 = —— = ——————— 1 25 </span>

<span>Equivalent fraction : </span>The fraction thus generated looks different but has the same value as the whole 

<span>Common denominator : </span>The equivalent fraction and the other fraction involved in the calculation share the same denominator

Adding fractions that have a common denominator :

<span> 2.2 </span>      Adding up the two equivalent fractions 
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

<span> x2 • 25 - (16) 25x2 - 16 —————————————— = ————————— 25 25 </span>Trying to factor as a Difference of Squares :

<span> 2.3 </span>     Factoring: <span> 25x2 - 16</span> 

Theory : A difference of two perfect squares, <span> A2 - B2  </span>can be factored into <span> (A+B) • (A-B)

</span>Proof :<span>  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 <span>- AB + AB </span>- B2 = 
        <span> A2 - B2</span>

</span>Note : <span> <span>AB = BA </span></span>is the commutative property of multiplication. 

Note : <span> <span>- AB + AB </span></span>equals zero and is therefore eliminated from the expression.

Check :  25  is the square of  5 
Check : 16 is the square of 4
Check : <span> x2  </span>is the square of <span> x1 </span>

Factorization is :       (5x + 4)  •  (5x - 4) 

<span>Equation at the end of step  2  :</span> (5x + 4) • (5x - 4) ——————————————————— = 0 25 <span>Step  3  :</span>When a fraction equals zero :<span><span> 3.1 </span>   When a fraction equals zero ...</span>

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the <span>denominator, </span>Tiger multiplys both sides of the equation by the denominator.

Here's how:

(5x+4)•(5x-4) ————————————— • 25 = 0 • 25 25

Now, on the left hand side, the <span> 25 </span> cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
   (5x+4)  •  (5x-4)  = 0

Theory - Roots of a product :

<span> 3.2 </span>   A product of several terms equals zero.<span> 

 </span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span> 

 </span>We shall now solve each term = 0 separately<span> 

 </span>In other words, we are going to solve as many equations as there are terms in the product<span> 

 </span>Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

<span> 3.3 </span>     Solve  :    5x+4 = 0<span> 

 </span>Subtract  4  from both sides of the equation :<span> 
 </span>                     5x = -4 
Divide both sides of the equation by 5:
                     x = -4/5 = -0.800 

Solving a Single Variable Equation :

<span> 3.4 </span>     Solve  :    5x-4 = 0<span> 

 </span>Add  4  to both sides of the equation :<span> 
 </span>                     5x = 4 
Divide both sides of the equation by 5:
                     x = 4/5 = 0.800 

<span><span> x = 4/5 = 0.800
</span><span> x = -4/5 = -0.800
</span></span>
3 0
3 years ago
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How do i solve 92-53.3
alexandr402 [8]

Answer:

the answer for 92-53.3 is 38.7

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