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JulijaS [17]
2 years ago
13

4. Is there a variable factor common to 24a and 6?​

Mathematics
1 answer:
Cloud [144]2 years ago
7 0

Answer:

There is no variable factor common to 24a and 6

Step-by-step explanation:

First number = 24a

Other number = 6

Pime factorisation of 24a = 2×2×3×2×a

Pime factorisation of 6= 3×2

Common factors = 6

Hence, there is no variable factor common to 24a and 6, Other common factor is 6.

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Graph the inequality on a number line. s < 1 1/2
ValentinkaMS [17]

Step-by-step explanation:

Put a open circle at 1 1/2 then draw a line going to the left of 1 1/2

5 0
2 years ago
I desperately need help !
Lorico [155]

Answer:

t = 9.57

Step-by-step explanation:

We can use trig functions to solve for the t

Recall the 3 main trig ratios

Sin = opposite / hypotenuse

Cos = adjacent / hypotenuse

Tan = opposite / adjacent.

( note hypotenuse = longest side , opposite = side opposite of angle and adjacent = other side )

We are given an angle as well as its opposite side length ( which has a measure of 18 ) and we need to find its adjacent "t"

When dealing with the opposite and adjacent we use trig ratio tan.

Tan = opp / adj

angle measure = 62 , opposite side length = 18 and adjacent = t

Tan(62) = 18/t

we now solve for t

Tan(62) = 18/t

multiply both sides by t

Tan(62)t = 18

divide both sides by tan(62)

t = 18/tan(62)

t = 9.57

And we are done!

3 0
2 years ago
Read 2 more answers
If y = kx, where k is a constant,<br> and y = 30 when x = 6, what is<br> the value of y when x = 3?
Svetradugi [14.3K]

Answer:

Step-by-step explanation:

Actually it's 11 because 11 is technically the same when added to constant of x =6 = 11

7 0
2 years ago
PLEASE HELP WILL GIVE BRIANLIEST!
IceJOKER [234]

Answer:

A"(1, -5)

B"(3, -5)

C"(4, -3)

D"(2, -3)

Step-by-step explanation:

When you are graphing coordinates make sure you have graph paper. When you plot the coordinates you reflect it over the x axis. The slide down 2 units down.

Hope this helps ☝️☝☝

3 0
2 years ago
After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos
igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P  and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}

and we found the distance PQ and QA

; d_{PQ}=\sqrt{125}, d_{QA}=12

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0
2 years ago
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