There are two numbers, one is 7 more than twice the other. The sum of the numbers is 43. Make the equation to find the smaller n
umber. Find the two numbers.
2 answers:
Answer:
The two numbers are 12,31.
I don't know the equation
The larger number is 2x + 7. The smaller number is x.
2x + 7 + × = 43
3x + 7 = 43
3x +7 -7 = 43 -7
3x = 36
3x/3 = 36/3
× = 12
checking...
2 (12) + 7 + 12 = 43
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Answer:
6
Step-by-step explanation:
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This would be written like this: 5>2n+1<7. Hope this helps.
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Step-by-step explanation:
