Answer:
1: C
2: A
3: B
Step-by-step explanation:
im not sure but i think this is it
Answer:
![\sqrt[3]{x^{10} }[\tex]Step-by-step explanation:Exponential Rules:[tex]x^{a} + x^{b} = x^{a + b}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EExponential%20Rules%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5Dx%5E%7Ba%7D%20%2B%20x%5E%7Bb%7D%20%3D%20x%5E%7Ba%20%2B%20b%7D)
![\sqrt[b]{x^{a} } =x^{\frac{a}{b} } Original Equation:[tex]\sqrt[3]{x^{10} } = x^{\frac{10}{3} } Answer:[tex]\sqrt[3]{x^{10} }[\tex]Convert the cubed root to a power. Cubed root = [tex]\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5Bb%5D%7Bx%5E%7Ba%7D%20%7D%20%3Dx%5E%7B%5Cfrac%7Ba%7D%7Bb%7D%20%7D%20%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EOriginal%20Equation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%20%20%3D%20x%5E%7B%5Cfrac%7B10%7D%7B3%7D%20%7D%20%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EAnswer%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3EConvert%20the%20cubed%20root%20to%20a%20power.%20Cubed%20root%20%3D%20%5Btex%5D%5Cfrac%7B1%7D%7B3%7D)

Convert them, so they have a common denominator - 


[tex]\sqrt[3]{x^{10} }[\tex] = [tex]x^{\frac{10}{3} } [\tex]
Answer:
P(compact cars) = 4/25 or .16
Step-by-step explanation:
<em>We know that there are </em><em>13 trucks, 8 vans, and 4 compact cars.</em>
<em />
<em>Let </em><em>P </em><em>denotes the probability of an event</em>
<em />
<em>Now we are asked to find the probability of compact cars</em>
<em />
<em>Number of favorable events = number of compact cars = 4</em>
<em />
<em>total number of outcomes </em><em>= 13+8+4 = 25</em>
<em>hence, P(compact cars) = number of favorable events/total outcomes</em>
<em> =4/25 or .16</em>
1. Find the "opposite side," if the angle is 60 degrees and the hyp is 6:
opp opp sqrt(3)
sin 60 deg = ------- = -------- = ----------
hyp 6 2
Cross-multiplying, 2(opp) = 6sqrt(3), so that opp = 3 sqrt(3) (answer)
2. Use the Pyth. Thm. to find the "adjacent side:"
[3sqrt(3)]^2 + x^2 = 6^2, or 9(3) + x^2 = 36, or x^2 = 9, or x = 3.
The lengths of the legs of this 30-60-90 triangle are 3 and 3 sqrt(3).
check: Does 3^2 + [3sqrt(3)]^2 = 6^2?
Does 9 + 9(3) = 6^2? YES