Let x and y be the two integers.
The sum of the integers is x+y while the difference is x-y assuming x is larger than y.
If x+y > x-y, then
x+y > x-y
x+y-x > x-y-x
y > -y
y+y > -y+y
2y > 0
2y/2 > 0/2
y > 0
So as long as y is positive, this makes the sum greater than the difference
For example, if x = 10 and y = 2, then
x+y = 10+2 = 12
x-y = 10-2 = 8
clearly 12 > 8 is true
If y is some negative number (say y = -4), then
x+y = 10+(-4) = 10-4 = 6
x-y = 10-(-4) = 10+4 = 16
and things flip around
Saying a blanket statement "the sum of two integers is always greater than their difference" is false overall. If you require y to be positive, then it works but as that last example shows, it doesn't always work.
So to summarize things up, I'd say the answer is "no, the statement isn't true overall"
Answer:
island C
Step-by-step explanation:
island C is 14 units away from island A, whereas island B is 20 units away
hope this helps!! :)
Okay. So you have the amount of take, and the tax rate.
To find tax you multiply the amount (x) by the percent of tax in decimal form.
So:
.06x = $1,080
x = $18,000
The equation is y= -2.
How? If you recall, a linear equation is y= mx+b. The m is the slope (growth) and b is the y-intercept ( where the line crosses the y-axis).
Now since there is no slope or m, the equation would look like this:
y= b or y= 0+b
Next, you want to input the coordinator points (0, -2) into the equation. reminder: (x, y) = x=0 y= -2
y= 0+ -2
y= -2
And there you go! The equation is y= -2. I hope I help you in solving this problem, if not message me, because I'll be glad to help you.
Example C: w cubed z, +, 5, z squared, minus z squared, +, 6 ..... For example, 2x + 1 = 7x and 10x minus 9y minus z = 3 are linear equations, but x, +, y ...
