Answer:
The number is 3
Step-by-step explanation:
Hi,
4 ( 3 + 5x) = 72
12 + 20x = 72
20x = 60
x = 3
Hope this helps :)
Answer:
D. y = { -x + 2 x ≥ 1}
{ x + 1 x < 1}
Step-by-step explanation:
First is to eliminate A and C, why?
This is because of the end points shown on the graph.
As shown, if you look at the point of (2,1) it is black, this means that not only is it closed but it is also means ≤ or ≥ symbol.
You are now left with B and D
The difference between these two is the symbols; they are facing the opposite directions.
While B says x ≤ 1, and x > 1
While D says x ≥ 1, and x < 1
The direction of the symbols depends on the direction of the lines and what is part of it (some what like a shaded area)
So you answer would be D
Answer:
Step-by-step explanation:
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Answer:
D
Step-by-step explanation:
You can look at it like a right triangle being made with the vertical part being 9 and the horizontal part being 8, then you want to find the diagonal part. So that's the Pythagorean theorem
Answer:
Step-by-step example explanation:
DOMAIN:
{
x
∣
x
≠
3
2
}
RANGE:
{
y
∣
y
≠
3
2
}
Explanation:
The domain consists of all numbers you can legally plug into the original. The excluded "illegal" values would be dividing by zero or negatives under square roots.
This expression has a denominator, so there is a risk of illegally dividing by zero. This would happen only if
2
x
−
3
=
0
2
x
=
3
x
=
3
2
This means that
x
=
3
/
2
is excluded from the domain. Therefore,
Domain: All real numbers except
x
=
3
/
2
. More formally, you could state the domain as
{
x
∣
x
≠
3
2
}
.
For rational functions, you find the range by evaluating the degree of the numerator compared to the degree of the denominator. If the degree of the top > degree of bottoms, then you have a horizontal asymptote at
y
=
0
. If they are equal, you have a horizontal asymptote. The coefficient of highest degree in the numerator is divided by the coefficient of the highest degree on the bottom. The result is
y
=
that fraction. So in our case, you have a horizontal asymptote at
y
=
3
2
