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STatiana [176]
3 years ago
14

20 points

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

0.125kg

Step-by-step explanation:

an equation can be made from teh problem

f(x)=1(0.5)^(x/5.3)

x is the amount of years

plug in 15.9 for x

f(15.9)=0.125

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Construct a quadrilateral ABCD in which AB = 4 cm, BC = 7 cm, angle A = angle C = 105 degree
Lelu [443]

Answer: see attachment

<u>Step-by-step explanation:</u>

Since A = C = 105° and D = 60°,

then A + B + C + D = 360°

     105° + B + 105° + 60° = 260°

               B + 270° = 360°

                          B = 90°      

     

7 0
4 years ago
6 divided by 2 and 1 fourths.<br> FULL ANSWER
enot [183]
6 divided by 2 and 1 forths is going to be 8 out of  3


4 0
3 years ago
Ben ran 3/10 of a mile. Shelly ran 8/10 of a mile. How many more miles did Shelly run than Ben? A) 11/10 B) 11/20 C) 5/0 D) 5/10
attashe74 [19]

Hello there! Shelly ran D) 5/10 more miles than Ben.

To find the difference between the two runner's distances, subtract the smaller distance from the greater distance.

8/10 - 3/10 = 5/10

Since there is a difference of 5/10, this means Shelly ran 5/1 more miles.

I hope this helps, & have a great rest of your day! :)

8 0
3 years ago
F(7) if f(x)=-3x-2 ​
Paul [167]

Answer:

f(7) = -23

Step-by-step explanation:

f(x) = -3x - 2

f(7) = -3(7) - 2

f(7) = -21 - 2 = -23

4 0
3 years ago
cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0
Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder=2\pi rh

Area of circular base=Area of circular top=\pi r^2

Total cost,C(r)=0.02\times 2\pi rh+2\pi r^2\times 0.07

Volume of cylinder,V=\pi r^2 h

200=\pi r^2 h

h=\frac{200}{\pi r^2}

Substitute the value of h

C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07

C(r)=\frac{8}{r}+0.14\pi r^2

Differentiate w.r.t r

C'(r)=-\frac{8}{r^2}+0.28\pi r

C'(r)=0

-\frac{8}{r^2}+0.28\pi r=0

0.28\pi r=\frac{8}{r^2}

r^3=\frac{8}{0.28\pi}=9.095

r=(9.095)^{\frac{1}{3}}=2.09

Again, differentiate w.r.t r

C''(r)=\frac{16}{r^3}+0.28\pi

Substitute the value of r

C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0

Therefore,the product cost is minimum at r=2.09

h=\frac{200}{\pi (2.09)^2}=14.57

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0
3 years ago
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