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Gre4nikov [31]
3 years ago
15

What is the pattern?

Mathematics
1 answer:
stealth61 [152]3 years ago
5 0

Answer:

I don't know sorry for your right question ok

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Shawn is coasting down a 500 \text{ cm}500 cm500, space, c, m long ramp on his inline skates. The wheels on his inline skates ar
Nata [24]

Answer: 16 rotations

Step-by-step explanation:

Given : Shawn is coasting down a 500 cm long ramp on his inline skates. The wheels on his inline skates are 32 cm in circumference.

Length of ramp = 500 cm

Circumference of wheels = 32 cm

Formula :

Number of rotations = Length of ramp divided by Circumference of wheels

= 500 cm ÷ 32 cm

= 15.625 ≈ 16   [approx]

Therefore, each wheel makes 16 rotations while Shawn is coasting down the ramp.

5 0
4 years ago
Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
Margaret [11]

Answer:

1. The minimum head breadth that will fit the clientele is of 4.41-in.

2. The maximum head breadth that will fit the clientele is of 7.19-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 5.8-in and a standard deviation of 0.8-in.

This means that \mu = 5.8, \sigma = 0.8

1. What is the minimum head breadth that will fit the clientele?

The 4.1st percentile, that is, X when Z has a pvalue of 0.041, so X when Z = -1.74.

Z = \frac{X - \mu}{\sigma}

-1.74 = \frac{X - 5.8}{0.8}

X - 5.8 = -1.74*0.8

X = 4.41

The minimum head breadth that will fit the clientele is of 4.41-in.

2. What is the maximum head breadth that will fit the clientele?

100 - 4.1 = 95.9th percentile, that is, X when Z has a pvalue of 0.959, so X when Z = 1.74.

Z = \frac{X - \mu}{\sigma}

1.74 = \frac{X - 5.8}{0.8}

X - 5.8 = 1.74*0.8

X = 7.19

The maximum head breadth that will fit the clientele is of 7.19-in.

8 0
3 years ago
Please please please please help me
Natali5045456 [20]

3(x - 3) + 8x = 5(2x + 1)

Expanding the terms,

3(x - 3) + 8x = 5(2x + 1) \\ 3x - 9 + 8x = 10x + 5

Collecting like terms,

3x - 9 - 8x = 10x + 5 \\ 3x - 8x - 10x = 5 + 9

Evaluating the terms,

3x - 8x - 10x = 5 + 9 \\  - 15x = 14

Divide both sides by -15,

- 15x = 14 \\ x =   - \frac{14}{15}

7 0
3 years ago
Read 2 more answers
Find the probability. A cooler contains fifteen bottles of sports drink: seven lemon-lime flavored and eight orange flavored. Yo
photoshop1234 [79]

Answer:

\dfrac{4}{15} \approx \bold{0.267}

Step-by-step explanation:

Given that:

Number of lemon - lime flavored bottles = 8

Number of orange flavored bottles = 7

Bottles are picked one by one.

First for the friend and then for the person himself.

To find:

The probability that both the bottles drawn are of lemon-lime flavor.

Solution:

Total number of bottles available in the cooler = 8 + 7 = 15

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

P(First\ lemon-lime) = \dfrac{8}{15}

Now, lemon - lime flavored bottles left = 7

Total number of bottles left = 14

P(Second\ lemon-lime)=\dfrac{7}{14}

Required probability:

P(Both\ lemon - lime) = \dfrac{8}{15}\times \dfrac{7}{14}\\\Rightarrow P(Both\ lemon - lime) = \dfrac{4}{15} \approx \bold{0.267}

6 0
3 years ago
PLEASE HELP!!!!!!<br><br> What is the remainder when the polynomial 4x^2+10x-4 is divided by 2x-1?
Andrei [34K]
The answer to the question

6 0
3 years ago
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