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allochka39001 [22]
3 years ago
7

Complete the second column of Table 11.02 with the

Computers and Technology
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

Explanation::::::

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To improve readability,______ use text on a dark green background.
Olenka [21]

To improve readability, use white text on a dark green background but <span>the darker text on a lighter background was rated more readable than lighter text on dark backgrounds according to survey in every color combination. Example, red text on white background is more readable than white text on red background.</span>


7 0
3 years ago
Read 2 more answers
Write a program that simulates flipping a coin repeatedly and continues until three consecutive heads. are tossed. At that point
quester [9]

Answer and Explanation:

#include <iostream>

#include <string>

#include <time.h>

#include <vector>

using namespace std;

//Takes user info

int user_info(string *name,char *gender){

   char G;

   cout<<"What is your name?: ";

   getline(cin, *name);

   cout<<"What is your gender(m/f):";

   cin>>G;

   cout<<endl;

   *gender = tolower(G);

   return 0;

}

//Toss coin(part 2)

bool coin_toss(double seed){

   double r;

   r = (double)seed/(double)RAND_MAX;

   //cout<<r;

   if (r<0.5) return true;

   return false;

}

//check results

float toss_result(vector<char> v,int *h){

   int num_heads=0;

   int num_toss = v.size();

   *h = 0;

   for(int i=0;i<num_toss;i++){

       if(v[i]=='h'){num_heads++;(*h)++;}

   }

   return (float)num_heads/(float)num_toss;

}

void show_result(int total_num,int head_num,float ratio){

   cout<<"it took you "<<total_num<<" tosses to get 3 heads in a row"<<endl;

   cout<<"on average you flipped heads "<<(ratio*100)<<"% of the time"<<endl;

}

int main()

{

   string name;

   char gender;

   string K; //Mr or Mrs

 

   cout<<"Welcome to coin toss! Get 3 heads in row to win!"<<endl;

 

   //part 1

   user_info(&name,&gender);

 

   if(gender == 'f') K = "Mrs.";

   else K = "Mr.";

 

   cout<<"Try to get 3 heads in a row. Good luck "<<K<<name<<"!"<<endl;

   char dummy = getchar();

 

   //part 2

   int num_toss;

   vector<char> toss_results;//store toss results

   bool result;//result of toss

   srand(time(0));

   while(true){

       //cout<<rand()<<endl;

       result = coin_toss(rand());

       cout<<"Press <enter> to flip"<<endl;

       while (1)

       {

           if ('\n' == getchar())

           break;

       }

     

 

     

       if(result) {toss_results.push_back('h');cout<<"HEAD"<<endl;}

       else {toss_results.push_back('t');cout<<"TAIL"<<endl;}

     

       num_toss = toss_results.size();

     

       if(num_toss>=3){

           if ((toss_results[num_toss-1] == 'h')&&(toss_results[num_toss-2] == 'h')&&(toss_results[num_toss-3] == 'h')){

               break;

           }

       }

   }

 

   //part 3

   float ratio_head;

   int num_of_heads;

   ratio_head = toss_result(toss_results,&num_of_heads);

 

   //part 4

 

   show_result(toss_results.size(),num_of_heads,ratio_head);

 

   return 0;

}

8 0
3 years ago
You are given a list of n positive integers a1, a2, . . . an and a positive integer t. Use dynamic programming to design an algo
Anna11 [10]

Answer:

See explaination for the program code

Explanation:

The code below

Pseudo-code:

//each item ai is used at most once

isSubsetSum(A[],n,t)//takes array of items of size n, and sum t

{

boolean subset[n+1][t+1];//creating a boolean mtraix

for i=1 to n+1

subset[i][1] = true; //initially setting all first column values as true

for i = 2 to t+1

subset[1][i] = false; //initialy setting all first row values as false

for i=2 to n

{

for j=2 to t

{

if(j<A[i-1])

subset[i][j] = subset[i-1][j];

if (j >= A[i-1])

subset[i][j] = subset[i-1][j] ||

subset[i - 1][j-set[i-1]];

}

}

//returns true if there is a subset with given sum t

//other wise returns false

return subset[n][t];

}

Recurrence relation:

T(n) =T(n-1)+ t//here t is runtime of inner loop, and innner loop will run n times

T(1)=1

solving recurrence:

T(n)=T(n-1)+t

T(n)=T(n-2)+t+t

T(n)=T(n-2)+2t

T(n)=T(n-3)+3t

,,

,

T(n)=T(n-n-1)+(n-1)t

T(n)=T(1)+(n-1)t

T(n)=1+(n-1)t = O(nt)

//so complexity is :O(nt)//where n is number of element, t is given sum

6 0
3 years ago
What are Three types of informational references
Irina-Kira [14]

Answer:

There are many types of information al references such as Encyclopedias, dictionaries, thesaurus Almanacs, atlases, thesauruses, Atlases, almanacs, and encyclopedias.

Explanation:

There are also informational websites. The way to find this is to look at the website url to see if it ends in .gov, .edu, and .org . But make sure you cite your source so you don't plagiarize.

If you don't have any questions feel free to ask in the comments.

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3 years ago
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Who is in the age range of 13-15 and wants to join a mine craft smp?
Ratling [72]

Answer: Wow that's really cool!

3 0
3 years ago
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