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3 years ago

How to use javascript libraries in javascript code?

1 answer:

3 0

When running in a browser, your source webpage should load the .js file containing the library, e.g.,:

<span><script type="text/javascript" src="<span>http://your.cdn.com/somelib.js</span>"></script>

In a stand-alone environment, like node.js, you use the require() statement:

</span><span>const crypto = require('crypto'<span>);

To load the required libraries, you use the package manager npm:

npm install crypto

This will create a local copy of the library.</span></span>

You might be interested in

Write a method reverse that takes an array as an argument and returns a new array with the elements in reversed order. Do not mo

mr Goodwill [35]

Answer:

public class ArrayUtils

{

//function to reverse the elements in given array

public static void reverse(String words[])

{

//find the length of the array

int n = words.length;

//iterate over the array up to the half

for(int i = 0;i < (int)(n/2);i++)

{

//swap the first element with last element and second element with second last element and so on.

String temp;

temp = words[i];

words[i] = words[n - i -1];

words[n - i - 1] = temp;

}

public static void main(String args[])

{

//create and array

String words[] = {"Apple", "Grapes", "Oranges", "Mangoes"};

//print the contents of the array

for(int i = 0;i < words.length;i++)

{

System.out.println(words[i]);

}

//call the function to reverse th array

reverse(words);

//print the contents after reversing

System.out.println("After reversing............");

for(int i = 0;i < words.length;i++)

{

System.out.println(words[i]);

}

Explanation:

4 0

2 years ago

3 uses of a computer

GenaCL600 [577]

Answer:

online bills payment

watching movies or shows

home tutoring

3 0

2 years ago

Read 2 more answers

You are called to assist in troubleshooting a network problem that has occurred soon after a significant IPv6 implementation. So

HACTEHA [7]

Answer:i dont kowe

Explanation:

5 0

3 years ago

100 points, PLEASE HELP...To generate numbers between and including -10 to 10 you would use:

Orlov [11]

Answer:

A number line?

6 0

3 years ago

CHALLENGE ACTIVITY |

fredd [130]

Answer:

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

The maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum.

Explanation:

This is where the statement will fit in the program.

#include <iostream>

using namespace std;

double FindMax(double num1, double num2) {

double maxVal = 0.0;

if (num1 > num2) { // if num1 is greater than num2,

maxVal = num1; // then num1 is the maxVal. }

else {

maxVal = num2; // num2 is the maxVal. }

return maxVal; }

int main() {

double numA;

double numB;

double numY;

double numZ;

double maxSum = 0.0;

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

cout << "maxSum is: " << maxSum << endl; }

Lets take an example to explain this. Lets assign values to the variables.

numA = 6.0

numB = 3.0

numY = 4.0

numZ = 9.0

maxSum =0.0

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

FindMax(numA,numB) method call checks if numA>numB or numB>numA and returns the maximum of the two. Here numA>numB because 6.0 is greater than 3.0. So the method returns numA i.e. 6.0

FindMax(numY, numZ) method call checks if numY>numZ or numZ>numY and returns the maximum of the two. Here numZ>numY because 9.0 is greater than 4.0. So the method returns numZ i.e. 9.0

FindMax(numA, numB) + FindMax(numY, numZ) this adds the two values returned by the method FindMax for each call.

FindMax returned maxVal from numA and numB values which is numA i.e. 6.0.

FindMax returned maxVal from numY and numZ values which is numZ i.e. 9.0.

Adding these two values 9.0 + 6.0 = 15

So the complete statement FindMax(numA, numB) + FindMax(numY, numZ) gives 15.0 as a result.

This result is assigned to maxSum. Hence

maxSum = 15

To see the output on the screen you can use the print statement as:

cout<<maxSum;

This will display 15

6 0

3 years ago