Answer:
double the bandwidth assigned per channel to 40 MHz
Explanation:
The best way of doing this would be to double the bandwidth assigned per channel to 40 MHz. This will make sure that the capacity is more than sufficient. This is simply because the bandwidth of a channel represents how much information can pass through the channel at any given second, the larger the channel, the more information/data that can pass at the same time. Therefore, if 20 MHz is enough for the network, then doubling this bandwidth channel size would be more than sufficient capacity for the network to handle all of the data.
Answer:
Given
The above lines of code
Required
Rearrange.
The code is re-arrange d as follows;.
#include<iostream>
int main()
{
int userNum;
scanf("%d", &userNum);
if (userNum > 0)
{
printf("Positive.\n");
}
else
{
printf("Non-positive, converting to 1.\n");
userNum = 1;
printf("Final: %d\n", userNum);
}
return 0;
}
When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;
One should take note of the variable declarations and usage
See attachment for .cpp file
Answer:
B
Explanation:
You need Name , Age and Gender
the second requirement should only match the last row where age is 20 and gender is male.
thrid requirement of the query is that its syntax should be correct.
Option B staisfies all of required so it is the correct option.
Answer:
WHAT SOCIETY?!
Every night we'd still be squatting in caves, hunched around campfires, waiting for the leopards to pick us off....
It's hard to have a society when your means of communication are nearly zero and therefore can't sustain the dialogue necessary to develop the shared values needed to form a society.
