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Andreas93 [3]
2 years ago
10

Line pass through the sets given points. which choice shows perpendicular lines?

Mathematics
1 answer:
Ludmilka [50]2 years ago
4 0

Answer:

I have no reference to this question, there is no graph or anything to show me.

Step-by-step explanation:

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Which function is shown in the graph below?
Georgia [21]

Answer:

D

Step-by-step explanation:

As you can see, the range of the graph is all real numbers greater than -4. Therefore you can tell that -4 will have to be in the equation leaving only options B and D. When graphing B and D, D fits the image.

4 0
3 years ago
I need X please and thank you
omeli [17]

Answer:

25.25

Step-by-step explanation:

7 0
3 years ago
SOMEONE PLEASE HELP ME OUT
zmey [24]

Answer:3/ 8 cause 123 and that’s 3 numbers and there is 8 numbers in total

3 0
3 years ago
Please simplify will give brainliyest
dimulka [17.4K]

   

\displaystyle\bf\\-\sqrt{m^4n^7}=\\\\=-\sqrt{m^{2\times2}\times n^{3\times2+1}}=\\\\=-\sqrt{m^{2\times2}\times n^{3\times2}\times n}}=\\\\=-\sqrt{\Big(m^2\Big)^2\times \Big(n^3\Big)^2\times n}}=\\\\=-\sqrt{\Big(m^2\times n^3\Big)^2\times n}}=\\\\=\boxed{\bf-m^2n^3\sqrt{n}}

 

4 0
3 years ago
how many different four letter permutations can be formed using four letters out of the first 12 in the alphabet?
Verizon [17]

Answer:

11,800 different four letter permutations can be formed using four letters out of the first 12 in the alphabet

Step-by-step explanation:

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

Permutations of four letters from a set of 12 letters. So

P_{(12,4)} = \frac{12!}{(12-4)!} = 11800

11,800 different four letter permutations can be formed using four letters out of the first 12 in the alphabet

3 0
2 years ago
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