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irga5000 [103]
3 years ago
15

What happens to a copper wire when it is moved across a magnetic field?

Physics
1 answer:
Arada [10]3 years ago
6 0

Answer:

it is attracted to negative pole

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A particle is confined to the x-axis between x = 0 and x = 1 nm. The potential energy U = 0 inside this region and U is infinite
DiKsa [7]

Answer:

Explanation:

According to heisenberg uncertainty Principle

Δx Δp ≥ h / 4π , where Δx  is uncertainty in position , Δp is uncertainty in momentum .

Given

Δx = 1 nm

Δp ≥ h /1nm x  4π

≥ 6.6 x 10⁻³⁴ / 10⁻⁹ x  4 π

≥  . 5254 x ⁻²⁵

h / λ ≥  . 5254 x ⁻²⁵

 6.6 x 10⁻³⁴ /. 5254 x ⁻²⁵ ≥ λ  

12.56 x 10⁻⁹ ≥ λ  

longest wave length = 12.56 n m

6 0
3 years ago
(a) A hole of 1 cm in diameter is drilled in a plate of steel at 20°C. What happens to the diameter of the hole as the steel is
Anestetic [448]

When heat is applied to a substance/material or steel in our case, a series of changes will occur, one of which is Expansion.

Hence the hole will expand from 1cm to a diameter that is greater.

Thermal expansion refers to the expansion or contraction of the dimensions of the solid, liquid or gas when their temperature is changed.

<h3>Types of Expansion</h3>
  • Linear expansion
  • Areal expansion and
  • Volumetric volume.

Learn more about expansion here:

brainly.com/question/1166774

8 0
3 years ago
A disc on a frictionless axle, starting from rest (0 rpm) can spin up to a rotation rate of 3820 rpm in a period of 2 seconds. (
Eddi Din [679]

Answer:

1000 Nm

2000 Nm

1.00007 seconds

Explanation:

I = Moment of inertia = 5 kgm²

\alpha = Angular acceleration

\omega_f = Final angular velocity

\omega_i = Initial angular velocity

t = Time taken

Torque is given by

\tau=I\alpha\\\Rightarrow \tau=5\times 200\\\Rightarrow \tau=1000\ Nm

The torque of the disc would be 1000 Nm

If \alpha=400\ rad/s^2

\tau=I\alpha\\\Rightarrow \tau=5\times 400\\\Rightarrow \tau=2000\ Nm

The torque of the disc would be 2000 Nm

From equation of rotational motion

\omega_f=\omega_i+\alpha t\\\Rightarrow t=\frac{\omega_f-\omega_i}{\alpha}\\\Rightarrow t=\frac{3820\times \frac{2\pi}{60}-0}{400}\\\Rightarrow t=1.00007\ s

It would take 1.00007 seconds to reach 3820 rpm

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4 years ago
What types of stars end their lives with supernovae?
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The type of star is the north star







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