Let x be the first
the second x +2
the third x+ 4
<span>twice the smallest 2x
</span><span>three times the largest 3(x+4 )
</span>2x + <span>3(x+4 )=42
</span>
2x +3x +12 = 42
5x= 30
x=6 the second is 8 the third is 10
We will first divide the interval [0,2] into 4 equal length subintervals each of length -------> (2-0)/4=1/2.
<span> The four subintervals are </span>
<span>[0,1/2], [1/2,1], [1,3/2], [3/2,2] and the endpoints of these subintervals are </span>
<span>0, 1/2, 1, 3/2, 2.</span>