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dem82 [27]
3 years ago
6

NEED HELP ASAPPP PLS

Mathematics
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

they are alternate interior angles to parallel lines.

Step-by-step explanation:

The reason for this is that they are alternate interior angles to parallel lines. The straight dotted lines that represent the line of sight of each individual are parallel to each other while the elevation line in this scenario would be considered the Transversal as it passes through both of them. This ultimately causes the angles between the transversal and the line of sight to be alternate interior angles which are equal to one another, as can be seen in the attached demonstration in the image below.

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Joanne buys a car for $1500 after 12 months Joanne is forced to sell the car for 10% less than what she brought it for, how much
MAVERICK [17]

Answer:

$1350

Step-by-step explanation:

Given she sold the car 10% less than what she bought it, amount she sold the car will be 10% of the amount she bought the car subtracted from the amount she bought he car .

She bought the car for $1500

Therefore,

10% of $1500

10% /100% x $1500

0.1 x $1500

$150

Now , amount she sold the car = $1500 - $150

= $1350

She sold the car for $1350

7 0
4 years ago
Tyler baked 702 cookies. and sold them is boxes of 18. after selling all of the boxes of cookies for the same amount each he ear
MAVERICK [17]
Why would someone need 702 cookies...?
5 0
3 years ago
Read 2 more answers
Solve irrational equation pls
rusak2 [61]
\hbox{Domain:}\\
x^2+x-2\geq0 \wedge x^2-4x+3\geq0 \wedge x^2-1\geq0\\
x^2-x+2x-2\geq0 \wedge x^2-x-3x+3\geq0 \wedge x^2\geq1\\
x(x-1)+2(x-1)\geq 0 \wedge x(x-1)-3(x-1)\geq0 \wedge (x\geq 1 \vee x\leq-1)\\
(x+2)(x-1)\geq0 \wedge (x-3)(x-1)\geq0\wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle1,\infty) \wedge x\in(-\infty,1\rangle \cup\langle3,\infty) \wedge x\in(-\infty,-1\rangle\cup\langle1,\infty)\\
x\in(-\infty,-2\rangle\cup\langle3,\infty)



\sqrt{x^2+x-2}+\sqrt{x^2-4x+3}=\sqrt{x^2-1}\\
x^2-1=x^2+x-2+2\sqrt{(x^2+x-2)(x^2-4x+3)}+x^2-4x+3\\
2\sqrt{(x^2+x-2)(x^2-4x+3)}=-x^2+3x-2\\
\sqrt{(x^2+x-2)(x^2-4x+3)}=\dfrac{-x^2+3x-2}{2}\\
(x^2+x-2)(x^2-4x+3)=\left(\dfrac{-x^2+3x-2}{2}\right)^2\\
(x+2)(x-1)(x-3)(x-1)=\left(\dfrac{-x^2+x+2x-2}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-x(x-1)+2(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\left(\dfrac{-(x-2)(x-1)}{2}\right)^2\\
(x+2)(x-3)(x-1)^2=\dfrac{(x-2)^2(x-1)^2}{4}\\
4(x+2)(x-3)(x-1)^2=(x-2)^2(x-1)^2\\

4(x+2)(x-3)(x-1)^2-(x-2)^2(x-1)^2=0\\
(x-1)^2(4(x+2)(x-3)-(x-2)^2)=0\\
(x-1)^2(4(x^2-3x+2x-6)-(x^2-4x+4))=0\\
(x-1)^2(4x^2-4x-24-x^2+4x-4)=0\\
(x-1)^2(3x^2-28)=0\\
x-1=0 \vee 3x^2-28=0\\
x=1 \vee 3x^2=28\\
x=1 \vee x^2=\dfrac{28}{3}\\
x=1 \vee x=\sqrt{\dfrac{28}{3}} \vee x=-\sqrt{\dfrac{28}{3}}\\

There's one more condition I forgot about
-(x-2)(x-1)\geq0\\
x\in\langle1,2\rangle\\

Finally
x\in(-\infty,-2\rangle\cup\langle3,\infty) \wedge x\in\langle1,2\rangle \wedge x=\{1,\sqrt{\dfrac{28}{3}}, -\sqrt{\dfrac{28}{3}}\}\\
\boxed{\boxed{x=1}}
3 0
3 years ago
The probability is 0.2 that a person shopping at a certain store will spend less than $20. For groups of size 17, find the mean
antiseptic1488 [7]

Steps:

1: p=0.2

2: n = 17

3: n*p= 17*0.2=3.4

Description:

The person will spend less than 20 or o.2 as seen in the question. Meaning p will equal 0.2. P for probability. Now n is for number. n will equal 17. And then we have to times all the number. N times P will equal 17 then times it by 0.2=  Answer will come as 3.4.

Answer: 3.4

The correct answer for this question is 3.4

Please mark brainliest

<em><u>Hope this helps.</u></em>

6 0
3 years ago
Lucy went to buy apples, she bought the first two for the full price and the last one for half the price. Is the relationship be
Anit [1.1K]
No it is not proportional. Since she brought the last apple for 1/2 the price, the equation won’t be linear (straight line) anymore so it won’t be proportional. Proportional means the same unit rate.
4 0
3 years ago
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