The decimal value of 16/32 is 0.5
:)
Answer:
non proportional
Step-by-step explanation:
All of the others are correct
Answer:
0.74 to 6.06
Step-by-step explanation:
The groups are independnet,
SE(xh bar-xa bar)=sqrt [sh^2/nh+sa^2/na]=sqrt [10.1^2/80+10.3^2/80]=1.61
At df=157, the t critical is 1.65
90%c.i=(xh bar-xa bar)+-tcritical SE(xh bar-xa bar)
=(25.2-21.8)+-1.65*1.61
=0.74 to 6.06
The answer is 2^(9/10). I did it assuming with the ^5 you mean the 5th root of 4
Lets suppose his initial weight was 60 kilograms
A gain of 20% would make his new eight 60 + 20*60/100
= 60 + 12
= 72 kg
he lost 25% of this:-
= 72 - 25 * 72/100 = 54 kg
This = (54/60) * 100 = 90% of his beginning weight Answer
