50 points! I only want mhanifa to help me so no one else answer unless you actually know how to do it
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Slope-intercept form:
y = mx + b
"m" is the slope, "b" is the y-intercept (the y value when x = 0) or (0,y)
For lines to be parallel, they have to have the SAME slope.
For lines to be perpendicular, their slopes have to be the opposite/negative reciprocals (flipped sign and number)
For example:
slope is 2
perpendicular line's slope is -1/2
slope is -2/3
perpendicular line's slope is 3/2
9.) First find the slope of line PQ. Use the slope formula and plug in the two points.
P = (4, 1) (x₁ , y₁)
Q = (8, 4) (x₂ , y₂)
Line RS is parallel to line PQ, so they have the same slope of 3/4
To find "b", plug in the point R = (3, -2) into the equation
Subtract 9/4 on both sides
Make the denominators the same
10.) Find the slope of line PQ
Line RS is perpendicular to line PQ, so the slope of line RS is -4/3
y = -4/3x + b
Plug in the point R = (3, -2) into the equation to find "b"
y = -4/3x + b
-2 = -4/3(3) + b
-2 = -4 + b Add 4 on both sides
2 = b