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sladkih [1.3K]
3 years ago
15

A store that sells shoes buys them from a manufacturer at a wholesale price of $57. The store's markup rate is 50%. What price d

oes the store charge its customers for the shoes? *
Mathematics
1 answer:
kogti [31]3 years ago
4 0
The answer is $85.50

57 x 50% or 57 x .5 = 28.50

Add $28.50 to $57 and you get $85.50
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We see that the second definition is not a good definition. We want both parts to have the same truth value, but we see that we can have two angles created by a ray that are not equal. That means the antecedent is false but the consequence is true, which means it's not an iff statement, and a bad definition in this context.

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3 years ago
Which of the following could be the first step in solving this problem? 9(12-3)+4
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Using P.E.M.D.A.S. ( parentheses exponent multiply divide add subtract ) you would multiply the nine into the parentheses
8 0
3 years ago
Teen obesity:
Law Incorporation [45]

Answer:

95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

Step-by-step explanation:

We are given that 15% of a random sample of 300 U.S. public high school students were obese.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

                        P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample % of U.S. public high school students who were obese = 15%

           n = sample of U.S. public high school students = 300

           p = population percentage of all U.S. public high school students

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

<u></u>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                             of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

  = [ 0.15-1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } } , 0.15+1.96 \times {\sqrt{\frac{0.15(1-0.15)}{300} } } ]

  = [0.110 , 0.190]

Therefore, 95% confidence interval for the percentage of all U.S. public high school students who are obese is [0.110 , 0.190].

6 0
3 years ago
How to write 92,542 in expanded form
marissa [1.9K]
92.542=9\cdot10.000+2\cdot1.000+5\cdot100+4\cdot10+2\cdot1 \\ =90.000+2.000+500+40+2
3 0
3 years ago
Read 2 more answers
Ellie and Heather drew floor models of their living rooms.Ellie's model represented 20 feet by 15 feet.Heather's model represent
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Ellies is 300 and heathers is 324 so it's greater4 by 24
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