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Phantasy [73]
3 years ago
13

The APR of Caesar's savings account is 3.6% and interest is compounded monthly the principal and Cesar savings account with $6,6

00 for an entire year what will be the balance of his account after the interest is paid for the year
Mathematics
2 answers:
ra1l [238]3 years ago
8 0

Answer:

6841 apex approved

Step-by-step explanation:

Kaylis [27]3 years ago
4 0

Answer:

$6841.56

Step-by-step explanation:

formula for compound interest is

A = P (1+\frac{r}{n})^{n*t}

P is the initial amount= 6600

r is the rate of interest = 0.036

t is the number of years = 1

n = compounded monthly = 12

plug in the values in the formula

A = 6600(1+\frac{0.036}{12})^{12*1}

A = 6600(1.003)^{12*1}

A= 6841.55986990

$6841.56 is the balance of his account after the interest is paid for the year


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Answer:

304

Step by step:

Using your calculator 5% of 320 is 16.

Since it was a discount, you subtract 16 since you're marking it down.

320-16=304

304 is your answer

How do I know? Well, there it takes 20+20+20+20+20 to equal a hundred. We can do this same math for this problem. 16 x 20 is 320

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olga2289 [7]

Answer:

x=0.25\,,\,y=1.75\,,\,z=0.25

Step-by-step explanation:

Let x,y,z denotes number of pencils, markers, erasers respectively.

For Andrea:

6x+7y+8z=15.75\,\,\,(i)

For Justin:

6x+8y+5z=16.75\,\,\,(ii)

For Virginia:

5x+5y+7z=11.75\,\,\,(iii)

On subtracting equations (i) and (ii), we get

(6x+7y+8z)-(6x+8y+5z)=15.75-16.75\\-y+3z=-1\\y-3z=1\\y=1+3z

Put y=1+3z in equation (i)

6x+7(1+3z)+8z=15.75\\6x+29z=8.75\,\,\,(iv)

Put y=1+3z in equation (iii)

5x+5(1+3z)+7z=11.75\\5x+22z=6.75\,\,\,(v)

Multiply equation (iv) by 5 and equation (v) by 6 and then subtract both the equations.

5(6x+29z)-6(5x+22z)=5(8.75)-6(6.75)\\13z=3.25\\z=\frac{3.25}{13}=0.25

Put z=0.25 in equation y=1+3z

y=1+3(0.25)=1.75

Put y=1.75\,,\,z=0.25 in equation (i)

6x+7(1.75)+8(0.25)=15.75\\6x+12.25+2=15.75\\6x=1.5\\x=0.25

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