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2 years ago

Write the slope-intercept form of the line given point and slope. ( show work if possible please)

Mathematics

1 answer:

irakobra [83]2 years ago

3 0

Answer:

y=5x+5

Step-by-step explanation:

y-y1=m(x-x1)

y-(-5)=5(x-(-2))

y+5=5(x+2)

y=5x+10-5

y=5x+5

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Recall that you can use the built-in functions rem(m,n) or mod(m,n)to find the remainder of the division m/n.

suter [353]

The answer is B hope this helped

5 0

3 years ago

Rewrite the following equation in standard form.<br> y + 7 = 2(x - 6)

babunello [35]

Answer:

(-5)

Step-by-step explanation:

(-5)+7=2(×-6) fahhshzhsuhshzhhsbwysvavaghahahahwhwgwvavvwhhwshahwh

4 0

2 years ago

3x-6y=9<br> x=2y+3<br><br> SOMEONE HELP ME SOLVE THIS STEP BY STEP TY

RideAnS [48]

Answer:

0=0

infinitely many solutions

Step-by-step explanation:

plug x=2y+3 as x into 3x-6y=9...so

3(2y+3)-6y=9, which has our x=2y+3 plugged in because that is what x equals

if you solve its

6y+9-6y=9

0y=0

y=0

making it 0=0

you can't go further from this

6 0

3 years ago

Suppose that

Diano4ka-milaya [45]

Answer:

sin(B) = 12/13

cos(B) = 5/13

tan(B) = 12/5

csc(B) = 13/12

sec(B) = 13/5

cot(B) = 5/12

Step-by-step explanation:

If ABC is a right triangle, assuming that ∠C = 90°, then the segment AB =13 is the hypotenuse and the other two sides are:

$BC = 5\\AC = \sqrt{13^2 - 5^2}\\AC = 12$

The six trigonometric functions of angle B are:

$sin(B) =\frac{AC}{AB}= \frac{12}{13}\\cos(B) = \frac{BC}{AB} =\frac{5}{13}\\tan(B) = \frac{AC}{BC} =\frac{12}{5}\\\csc(B) =\frac{1}{sin(B)}= \frac{13}{12}\\sec(B) = \frac{1}{cos(B)} =\frac{13}{5}\\cot(B) = \frac{1}{tan(B)} =\frac{5}{12}\\$

7 0

3 years ago

Does someone mind helping me with this?

Contact [7]

Answer:

should be the 1st 2nd and the 4th one

Step-by-step explanation:

if not correct plz tell me

3 0

3 years ago