Question

How do you write -x+3y=6 in point-slope form?

Answer 1

• Point-Slope form: $y-y_1=m(x-x_1)$ , with $(x_1,y_1)$ as a point on the line and m = slope
• Slope-Intercept form: $y=mx+b$ , with m = slope and b = y-intercept.
• Slope Formula: $\frac{y_2-y_1}{x_2-x_1}$

So firstly, we have to convert this standard form equation into slope-intercept form. To start with, add x on both sides of the equation: $3y=x+6$

Next, divide both sides by 3 and your slope-intercept form is $y=\frac{1}{3}x+2$ .

Next, since we know one of the points, the y-intercept (0,2), and the slope, 1/3. We can use the slope formula to get to point-slope form. Our equation looks like this:

$\frac{y-2}{x-0}=\frac{1}{3}\\\\\frac{y-2}{x}=\frac{1}{3}$

For this, just multiply both sides by x and your point-slope form is $y-2=\frac{1}{3}(x)$

Answer 2

Point slope form is y-y1= m(x-x1)
So u need another x and y ull hav to guess with what u hav so like it could start as 2-1 or 3-0 but it’s ur choice