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kari74 [83]
3 years ago
7

A rectangle has a length of 6 inches and a width of 8 inches. A square with a side length of 3 was cut out of it. What is the ar

ea of the remaining paper
Mathematics
1 answer:
Colt1911 [192]3 years ago
6 0

Answer: 39 inch²

Step-by-step explanation:

The rectangle's area was:

= Length * Width

= 6 * 8

= 48 inches²

The square's area is:

= Length * width

= 3 * 3

= 9 inches²

The square was cut out of the rectangle which means the area of the square should be deducted from the rectangle to find out the remaining area.

= 48 - 9

= 39 inch²

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For which of the following increasing functions f does (f-1)'(20) = 1/5
aalyn [17]

Answer:

D f(x)= e^x+ 5x + 19

Step-by-step explanation:

D f(x)= e^x+ 5x + 19

5 0
3 years ago
The temperature is -5°C at sunrise. By noon, the temperature changes by 6°C what could be the temperature at noon? answer asap !
Citrus2011 [14]

Answer:

the temperature is -5C which is negative so its behind the zero on a number line  and 6C is positive which is infront of the zero so it would be 1C by noon

Step-by-step explanation:

3 0
3 years ago
Can u solve the answer
pickupchik [31]

Answer:

She needs 50 ft² of wood to cover the table

Step-by-step explanation:

You need to know the formula for area of a trapezoid, which is

A = (B1 + B2)h/s     (add the bases together, multiply by the height, then divide

                                by 2)

We are given B1 = 12, B2 = 8, and h = 5, so plug them in and simplify

A = (12 + 8)(5)/2

 

    A = (20)(5)/2

       A = 100/2

         A = 50 ft²

5 0
3 years ago
The ratio of pencils to erasers is 4:1 if there are 20 pencils how many erasers are there? Kerion has a beaded necklace business
Misha Larkins [42]

Answer:

we express the ratio of pencil to eraser and multiply it by the number of the number of pencils and erasers. 4/5 * x=20 , so x=25, then it implies that there are 5 erasers.

7 0
4 years ago
F(x) = 2x^2 - 3x, calculate f(x+h)-f(x) / h
kvasek [131]
First plug in (x+h) for x in the function.
f(x+h)= 2(x-h)^2-3(x-h) = 2(x^2-2xh+h^2)-3x-3h =
2x^2-4xh+2h^2-3x-3h - 2x^2 +3x =
(-4xh +2h^2-3h)/h
-4x +2h-3
6 0
4 years ago
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