1.77777777778 would be the answer you are looking for I think.
The answer is -9. Have a great day
(4x-3y)^2(4x-3y)
=(16x^2-24xy+9y^2)(4x-3y)
=64x^3-96x^2y+36xy^2-48x^2y+72xy^2-27y^3
=64x^2-144x^2y+108xy^2-27y^3
Step-by-step explanation:
Use arc length:
s = rθ
where r is the radius and θ is the angle in radians.
a) First, convert the angle to radians (1 degree = 60 minutes).
77 ⁵⁰/₆₀° × (π radian / 180°) = 1.358 radians
s = rθ
s = (9.67 in) (1.358 rad)
s = 13.1 in
b) s = rθ
4 in = (9.67 in) θ
θ = 0.414 radians
θ = 23.7°
θ = 23° 42'
A straight line passing through the point (-2,1) and having a gradient of -3 yields the equation y = -3x - 5.
We know that a straight line is an infinitely long line with no curves on it. A straight line's equation is
y = mx + c...(1), where m is the gradient of the straight line and c is a constant.
Given that the gradient of the given straight line = m = -3.
Putting this value in (1), we get
y = -3x + c ...(2)
Again, the given straight line passes through the point (-2,1). So, we can put x = -2 and y = 1 to get the value of the constant c.
So, 1 = (-3)(-2) + c
i.e. 6 + c = 1
i.e. c = 1 - 6 = -5
(2) can be written as
y = -3x - 5
Therefore the equation of the given straight line is
y = -3x - 5
Know more about straight lines here -
brainly.com/question/8085796
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