Answer:
Step-by-step explanation:
radius=4 as it is tangent to x-axis.
y co-ordinate of center is 4 so radius=4
eq. of circle is (x-2)²+(y-4)²=4²
or x²-4x+4+y²-8y+16=16
or x²+y²-4x-8y+4=0
X－7y＝7
To find the x-intercept, substitute y＝0
x－7×0＝7
x－0＝7
x＝7
∴ the x-intercept of the line is (7,0)
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
Learn more about computations on:
brainly.com/question/4658834
#SPJ4
Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
D) -0.87
Step-by-step explanation:
I took this test don't quote me on the answer but this is what my peers put.
