9514 1404 393
Answer:
3a by 4a
Step-by-step explanation:
For dimensions L and W, the area and perimeter are ...
A = LW = 12a^2
P = 2(L+W) = 14a
Using the second equation, we can find L:
L +W = 7a . . . . . divide by 2
L = 7a -W
Substituting into the area formula gives the quadratic ...
(7a -W)(W) = 12a^2
W^2 -7aW +12a^2 = 0 . . . . arrange in standard form
(W -3a)(W -4a) = 0 . . . . . . . factor (find factors of 12 that total 7)
Then we have the two solutions ...
W = 3a, L = 4a
W = 4a, L = 3a
The rectangle dimensions are 3a by 4a.
4/5÷2/3=x
4/5×3/2=x
12/10=x
1 1/5=x
Answer:
1) 13 ft
Step-by-step explanation:
1) 13+8=21 which is greater than 15. Would be a triangle.
2) 7+8=15 This would be a single line, not a triangle.
3) 3+8<15 This would be a single line, not a triangle.
2) 15+8=23 This would be a single line, not a triangle.
$12 5 times 3 is 15 -20% is $12
