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3 years ago

Please my dog just farted

Mathematics

1 answer:

8090 [49]3 years ago

6 0

Answer:

perimeter = 4 x side

perimeter = 4(4x–1) = 16x – 4

Step-by-step explanation:

Please correct me if I am wrong :)

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Use l'Hôpital's Rule to find the following limit. ModifyingBelow lim With x right arrow 0StartFraction 3 sine (x )minus 3 x Ove

steposvetlana [31]

Answer:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=-\frac{1}{14}$

Step-by-step explanation:

The limit is:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{0}{0}$

so, you have an indeterminate result. By using the l'Hôpital's rule you have:

$\lim_{x \to 0} \frac{a(x)}{b(x)}= \lim_{x \to 0} \frac{a'(x)}{b'(x)}$

by replacing, and applying repeatedly you obtain:

$\lim_{x \to 0} \frac{3sinx-3x}{7x^3}= \lim_{x \to 0}\frac{3cosx-3}{21x^2}= \lim_{x \to 0}\frac{-3sinx}{42x}= \lim_{x \to 0}\frac{-3cosx}{42}\\\\ \lim_{x \to 0} \frac{3sinx-3x}{7x^3}=\frac{-3cos0}{42}=-\frac{1}{14}$

hence, the limit of the function is -1/14

8 0

3 years ago

Please help I’ll give brainiest!<br><br> Make sure to tell me steps by steps!:D

asambeis [7]

Answer:

see below

Step-by-step explanation:

h(x) = 2x-10

Let x=3

h(3) = 2*3 -10

= 6-10

Let x=-3

h(-3) = 2*-3 -10

= -6-10

=-16

6 0

3 years ago

HELP QUICK PLZ!!!

yulyashka [42]

B. 12 is the answer to your queation

7 0

3 years ago

Change this radical to an algebraic expression with fractional exponents.

vekshin1

Rational exponents

$a^\frac{m}{n}$

work like this: the numerator is the actual exponent of the base, while the denominator is the index of the root.

In other words, we have

$a^\frac{m}{n}=\sqrt[n]{a^m}$

So, in you case, we have

$\sqrt[5]{x^3}=x^\frac{3}{5}$

Assuming that the question contanis a typo. If you actually mean $5\sqrt{x^3}$ ,

then you can write it as $5x^\frac{1}{3}$

7 0

3 years ago

If g ( x ) = 5 − 3x², find g(-2) =

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

g(-2) = 5 - 3(-2)^2 = 5 - 3(4) = 5 - 12 = -7

5 0

3 years ago

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Please my dog just farted​

Please my dog just farted