<h2><u>Math</u><u> </u><u>Problem</u><u> </u></h2>
<u>If</u><u> </u><u>die</u><u> </u><u>is</u><u> </u><u>rolled</u><u> </u><u>two</u><u> </u><u>times</u><u>,</u><u> </u><u>find</u><u> </u><u>the</u><u> </u><u>probably</u><u> </u><u>of</u><u> </u><u>getting</u><u> </u><u>"</u><u>1'twice</u><u>.</u>
<h2><u>Math</u><u> </u><u>Answer</u><u> </u></h2>
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<u>Feel</u><u> </u><u>fre</u><u> </u><u>e</u><u> </u><u>too</u><u> </u><u>ask</u><u> </u><u>me</u><u> </u>
<u>Please</u><u> </u><u>understand</u><u> </u><u>it</u>
<u>#BrainliestBunch</u>
Loge 70.81 = a
Log to the base e is also written as ln
ln 70.81 = a
Answer:
79% - almost 4 times out of 5.
The key to this is realizing that the number of games will not always be 5.
If A wins in a sweep - you have 2/3*(2/3)*2/3 percent chance of that happening - 8/27, or 29.63%
If A wins in 4, now we have 2/3*(2/3)*2/3*(1/3)*3 - the 1/3 is the chance that B wins a game. Note - there are only 3 ways B can win a game, not 4. B cannot win Game 4 because Game 4 would not be played in case of a sweep. That is why you cannot use a straight Pascal’s triangle to get your coefficients - the 1–4–6–4–1 is not possible if B cannot win Game 4. Anyway, the math is the same as the above, a 29.63% chance of A winning in 4.
For a 5 game set, A could lose 2 games in 6 possible ways (lose 1&2, 1&3, 1&4, 2&3, 2&4 or 3&4). Again, A cannot lose Game 5 - it would not be played once A wins 3 games. So the odds become 2/3*(2/3)*2/3*(1/3)*(1/3)*6, or 19.75%.
Add them up and you get 79.01%
Step-by-step explanation:
Hope it helps<3
Answer:
x=6,-4
Step-by-step explanation:
Ok so we know the 2 angles are congruent so you need to set them equal to each other. x^2+5x=7x+24. Then get the x's together so you subtract by 7x to get x^2-2x=24. You would then get 24 on the other side so subtract by 24 to get x^2-2x-24. You then would need to factor the equation out. The factored form would be (x-6)(x+4). Then set it equal to 0 to get 6 and -4.