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OLga [1]
3 years ago
5

Fourteen hours after a convict escapes from prison, a guard begins to pursue him. If the convict travels at eight mph on foot an

d the guard travels at 64 mph by car, how far from the prison will the convict be caught by the guard?
Mathematics
1 answer:
algol133 years ago
8 0

9514 1404 393

Answer:

  128 miles

Step-by-step explanation:

The convict has a head start of ...

  distance = speed × time

  distance = (8 mi/h) × (14 h) = 112 mi

That distance is being closed at a rate that is the difference between the speeds, so ...

  64 mi/h -8 mi/h = 56 mi/h

The time it takes the guards to catch the convict will be ...

  time = distance/speed

  time = (112 mi)/(56 mi/h) = 2 h

The guards and prisoner will be at a distance from the prison of ...

  distance = speed × time

  distance = (64 mi/h)(2 h) = 128 mi

The convict will be caught 128 miles from the prison.

__

<em>Check</em>

The convict will run an additional (8 mi/h)(2 h) = 16 mi after the guards start pursuit. That, in addition to the 112 miles already run, will total 112+16=128 miles, the same distance the guards travel in that 2 hours.

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