110x0.7= 77
110-77= 33
so 33 is your answer
Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
50 1/2 = 50.5
50.5 + -12.3
When adding a negative number to a positive number, it basically becomes just subtraction so 50.5 + -12.3 means 50.5 - 12.3
50.5 - 12.3 = 38.2
Uhhhhhhh I don't really know look on quizlet
√25/4=5/2 because 5/2 times 5/2 equal 25/4. Hope it help!
