Answer:
7, 22, 39 hope this helps :)
Step-by-step explanation:
It’s adding 7, then 9, then 11, and so on.
I think the answer is 5x + 6y + 1
<span>The measure standard deviation quantifies the amount of variation or dispersion of a set of data values.</span>The standard deviation is the square root of the variance.
The standard deviation in this case is 50/ sqrt(100)= 50/10=5.
Answer:
So we use the t-distribution to compute a confidence interval for the average age of people using online dating services
Step-by-step explanation:
Confidence interval for a mean.
We have to decide between the t-distribution and the z-distribution.
T-distribution: We use the sample standard deviation.
Z-distribution: We use the population standard deviation.
In this problem:
The average age of those that were using online dating services was 35 years old with a sample standard deviation of 12 years.
So we use the t-distribution to compute a confidence interval for the average age of people using online dating services
Normally you would only solve by completing the square if a is 1 and b is even. But the answer would be half of b. So half of 9 is 4.5 or 4(1/2).