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Sunny_sXe [5.5K]
3 years ago
14

Complete these. Show your thinki b. 3.25 ft = in HELPPPP

Mathematics
1 answer:
Ainat [17]3 years ago
7 0

Answer:

35 inches

Step-by-step explanation:

multiply length value by 12

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What is the value for x?
schepotkina [342]
Right of the bat, I know the measure of angle C equals 73° because of the Isosceles Base Angle Theorem. Then, due to the Triangle Sum Theorem, I know that all of the measures in the triangle must add to 180°. To find this, just subtract 73 and 73 from 180. Finally, because angle B equals (6x + 4) and 34°, just set them equal to each other to find the value of x.


180 - 73 - 73 = measure of angle B
34° = measure of angle B

6x + 4 = 34
      - 4    - 4
6x = 30
6x / 6 = 30 / 6
x = 5

Hope this helps!
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What are the coordinates of the center of a circle whose equation is (x + 10)2 + (y – 8)2 = 17?
Sonja [21]

we just need make inside square 0

x+10=0

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Ilia_Sergeevich [38]
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3 years ago
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Linda has 4 2/3 yards of material . She is making baby clothes for the bazzaar. Each dress patterns requries 1/16 yards of mater
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4 0
4 years ago
Does the table show a direct proportional relationship? If so, what is the constant of proportionality?
lesantik [10]

Answer:

C. Yes, 3.5.

Step-by-step explanation:

If there is a relationship of direct proportionality for every ordered pair of the table, then the constant of proportionality must the same for every ordered pair. The constant of proportionality (k) is described by the following expression:

k = \frac{y}{x} (1)

Where:

x - Input.

y - Output.

If we know that (x_{1}, y_{1}) = (13, 45.5), (x_{2}, y_{2}) = (14, 49) and (x_{3}, y_{3}) = (15, 52.5), then the constants of proportionalities of each ordered pair are, respectively:

k_{1} = \frac{y_{1}}{x_{1}}

k_{1} = \frac{45.5}{13}

k_{1} = \frac{7}{2}

k_{2} = \frac{y_2}{x_2}

k_{2} = \frac{49}{14}

k_{2} = \frac{7}{2}

k_{3} = \frac{y_{3}}{x_{3}}

k_{3} = \frac{52.5}{15}

k_{3} = \frac{7}{2}

Since k_{1} = k_{2} = k_{3}, the constant of proportionality is 3.5.

8 0
3 years ago
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