Answer: No
Currently we don't have enough information to prove this quadrilateral is a parallelogram. One piece of information that would be useful would be if the other diagonal is bisected. If that's the case, then we have a parallelogram (we would first prove the triangles congruent and then use the corresponding congruent angles to set up the parallel lines). Unfortunately, we only know about one diagonal being bisected, but not both, so we don't have enough info.
Answer: 1.83
Step-by-step explanation: 1 2/9 divided by 2/3 = 1.83
Yes, it's true.
<em>Every </em><em>rectangle</em><em> </em><em>is </em><em>a </em><em>parallelogram</em><em>,</em><em> </em><em>but </em><em>not </em><em>every </em><em>parallelogram</em><em> </em><em>is </em><em>rectangle.</em><em> </em>
So, every parallelogram's properties will be same to rectangle, but not every rectangle's property will be same as parallelogram.
<u>Hope </u><u>it </u><u>helps</u><u> </u><u>ya!</u><u> </u>
Answer:
The surface area is 
Step-by-step explanation:
we know that
The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces
so
![SA=b^{2}+4[\frac{1}{2}(b)(l)]](https://tex.z-dn.net/?f=SA%3Db%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28l%29%5D)
where
-----> the slant height
substitute the values
![SA=9^{2}+4[\frac{1}{2}(9)(12)]](https://tex.z-dn.net/?f=SA%3D9%5E%7B2%7D%2B4%5B%5Cfrac%7B1%7D%7B2%7D%289%29%2812%29%5D)
Step-by-step explanation:
