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Tamiku [17]
3 years ago
11

An Ice company charges $8.16 for 6 bags of ice. If you buy 8 bags of ice how much would it cost you? help asap its due tomorrow

Mathematics
2 answers:
nataly862011 [7]3 years ago
8 0

Answer:

fjsij

Step-by-step explanation:

yjjgghhhhggn

gjjdghjhc

hhhhjjhhhhiiiigffjhcvfhhsfh

Nata [24]3 years ago
8 0

Answer:

Answer:$10.88

Step-by-step explanation:

First we need to see how much one bag of ice costs. To do this we need to divide 8.16 by 6.

8.16÷6=1.36

Now that we know how much a bag of ice cost we need to calculate how much 8 bags costs. This means we have to multiply 1.36 by 8.

1.36x8= 10.88.

The answer is $10.88

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The answer would be negative 1

Step-by-step explanation:

The reason why it is negative one is because you line them up and yeah.

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3 years ago
Which expression is equivalent to 2^2divided by 2/2^4
Gnesinka [82]

Answer: 32

Step-by-step explanation:

The expression that is equivalent to 2^2 divided by 2/2^4 would be calculated as:

= 2^2 ÷ 2/2^4

= 4 ÷ 2/16

= 4 ÷ 1/8

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The expression would be equal to 32 based on the above calculation

4 0
3 years ago
Find the inverse of this matrix.<br> 1 -1 -1<br> -1 2 3 <br> 1 1 4
zheka24 [161]

Let's use Gaussian elimination. Consider the augmented matrix,

\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\-1 & 2 & 3 & 0 & 1 & 0\\1 & 1 & 4 & 0 & 0 & 1\end{array}\right]

• Add row 1 to row 2, and add -1 (row 1) to row 3:

\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 2 & 5 & -1 & 0 & 1\end{array}\right]

• Add -2 (row 2) to row 3:

\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 2 & 1 & 1 & 0\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]

• Add -2 (row 3) to row 2:

\left[\begin{array}{ccc|ccc}1 & -1 & -1 & 1 & 0 & 0\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]

• Add row 2 and row 3 to row 1:

\left[\begin{array}{ccc|ccc}1 & 0 & 0 & 5 & 3 & -1\\0 & 1 & 0 & 7 & 5 & -2\\0 & 0 & 1 & -3 & -2 & 1\end{array}\right]

So the inverse is

\begin{bmatrix}1&-1&-1\\-1&2&3\\1&1&4\end{bmatrix}^{-1} = \boxed{\begin{bmatrix}5&3&-1\\7&5&-2\\-3&-2&1\end{bmatrix}}

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3 years ago
2. it's not B
Tanzania [10]

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

( 0 ,   1 )

Equation Form:

x = 0 ,     y = 1

Step-by-step explanation:

Graph.

y = − 5/ 2 x − 1

y = 3 x − 1

y = 2/ 5 x + 1

y = 5/ 3 x + 1

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3 years ago
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2.5 should be correct?
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