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forsale [732]
2 years ago
9

If 47 Mph was a unit rate, how many hours would it take to travel 1 Mph?

Mathematics
2 answers:
insens350 [35]2 years ago
8 0

Answer: um i think you asked the question wrong. But ok.

Step-by-step explanation:

= 47 miles per hour

This is a fraction equal to

47 miles ÷ 1 hours

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 1

47 miles ÷ 1

1 hours ÷ 1

=  

47 miles

1 hour

=  

47 miles

hour

= 47 miles per hour

melomori [17]2 years ago
4 0

Answer:

It would take you a total of .021 of an hour to get there.

Step-by-step explanation:

So, you are asking if 47 mph was a unit rate, how long would it take to travel 1 mile? Ok, so you would convert this to a unit rate, which would be 1 hour.47 miles because you are trying to get the 47 to a 1. Next, you will divide both numbers by 47, giving you .0212765957/1. This rounds to .021/1.

Hope this helps! :)

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3/1

Step-by-step explanation:


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Evaluate -9x+3y+4 for x=5 and y=7
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Answer:

\displaystyle -20

Step-by-step explanation:

\displaystyle -9[5] + 3[7] + 4 = -45 + 21 + 4 = -20

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Terra wants wall-to-wall carpeting in her bedroom, which measures 10’ x 12’6”. Carpeting is on sale for $24.99 per sq. yd. What
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$347.08

Step-by-step explanation:

10' x 12'6" = 125 ft^2

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Part 4: Use the information provided to write the vertex formula of each parabola.
sergey [27]

Answer:  1. x = (y - 2)² + 8

              \bold{2.\quad x=-\dfrac{1}{2}(y-10)^2}+1

               3. y = 2(x +9)² + 7

<u>Step-by-step explanation:</u>

Notes: Vertex form is: y =a(x - h)² + k    or      x =a(y - k)² + h

  • (h, k) is the vertex
  • point of vertex is midpoint of focus and directrix:   \dfrac{focus+directrix}{2}

     \bullet\quad a=\dfrac{1}{4p}

  • p is the distance from the vertex to the focus

1)

focus = \bigg(\dfrac{-31}{4},2\bigg)\qquad directrix: x=\dfrac{-33}{4}\\\\\text{Since directrix is x, then the x-value of the vertex is:}\\\\\dfrac{focus+directrix}{2}=\dfrac{\frac{-31}{4}+\frac{-33}{4}}{2}=\dfrac{\frac{-64}{4}}{2}=\dfrac{-16}{2}=-8\\\\\text{The y-value of the vertex is given by the focus as: 2}\\\\\text{vertex (h, k)}=(-8,2)

Now let's find the a-value:

p=focus-vertex\\\\p=\dfrac{-31}{4}-\dfrac{-32}{4}=\dfrac{1}{4}\\\\\\a=\dfrac{1}{4p}=\dfrac{1}{4(\frac{1}{4})}=\dfrac{1}{1}=1

Now, plug in a = 1   and    (h, k) = (-8, 2) into the equation x =a(y - k)² + h

x = (y - 2)² + 8

***************************************************************************************

2)

focus = \bigg(\dfrac{1}{2},10\bigg)\qquad directrix: x=\dfrac{3}{2}\\\\\text{Since directrix is x, then the x-value of the vertex is:}\\\\\dfrac{focus+directrix}{2}=\dfrac{\frac{1}{2}+\frac{3}{2}}{2}=\dfrac{\frac{4}{2}}{2}=\dfrac{2}{2}=1\\\\\text{The y-value of the vertex is given by the focus as: 10}\\\\\text{vertex (h, k)}=(1,10)

Now let's find the a-value:

p=focus-vertex\\\\p=\dfrac{1}{2}-\dfrac{2}{2}=\dfrac{-1}{2}\\\\\\a=\dfrac{1}{4p}=\dfrac{1}{4(\frac{-1}{2})}=\dfrac{1}{-2}=-\dfrac{1}{2}

Now, plug in a = -1/2   and    (h, k) = (1, 10) into the equation x =a(y - k)² + h

\bold{x=-\dfrac{1}{2}(y-10)^2}+1

***************************************************************************************

3)

focus = \bigg(-9,\dfrac{57}{8}\bigg)\qquad directrix: y=\dfrac{55}{8}\\\\\text{Since directrix is y, then the y-value of the vertex is:}\\\\\dfrac{focus+directrix}{2}=\dfrac{\frac{57}{8}+\frac{55}{8}}{2}=\dfrac{\frac{112}{8}}{2}=\dfrac{14}{2}=7\\\\\text{The x-value of the vertex is given by the focus as: -9}\\\\\text{vertex (h, k)}=(-9,7)

Now let's find the a-value:

p=focus-vertex\\\\p=\dfrac{57}{8}-\dfrac{56}{8}=\dfrac{1}{8}\\\\\\a=\dfrac{1}{4p}=\dfrac{1}{4(\frac{1}{8})}=\dfrac{1}{\frac{1}{2}}=2

Now, plug in a = 2   and    (h, k) = (-9, 7) into the equation y =a(x - h)² + k

y = 2(x +9)² + 7

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