Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
Answer:
8x-18
Step-by-step explanation:
ggv dcbbccc. bvvccv. vccbv. vvvvv
Answer:
X = 48
Step-by-step explanation:
When you type sin(42) in your calculator it will give you something around 0.669.
If you try reverse sinus sin-1(0.669) it will give you 42.
Therefore you can say that:
Cos(x) = 0.669
So you can reverse the cos to get your answer
Cos-1(0.669) = 48
Or
Cos-1 (sin(42))
First can you change
2x + y = -12
To have y as the subject
Looks like y = ???