Determine the type of triangle that is drawn below.

Multiply the polynomial <br><br> (4d-3)(-2d+1)

Nutka1998 [239]

If this an it my bad Gee

8 0

2 years ago

What is the answer to f(x)=x^2-10x+4 f(-2)

Maru [420]

Answer:

Step-by-step explanation:

f(x)=4+20+4

=28

3 0

2 years ago

Seventy percent of all vehicles examined at a certain emissions inspection station pass the inspection. Assuming that successive

LenaWriter [7]

Answer:

(a) The probability that all the next three vehicles inspected pass the inspection is 0.343.

(b) The probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c) The probability that exactly 1 of the next three vehicles passes is 0.189.

(d) The probability that at most 1 of the next three vehicles passes is 0.216.

(e) The probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

Step-by-step explanation:

Let <em>X</em> = number of vehicles that pass the inspection.

The probability of the random variable <em>X</em> is <em>P (X) = 0.70</em>.

(a)

Compute the probability that all the next three vehicles inspected pass the inspection as follows:

P (All 3 vehicles pass) = [P (X)]³

$=(0.70)^{3}\\=0.343$

Thus, the probability that all the next three vehicles inspected pass the inspection is 0.343.

(b)

Compute the probability that at least 1 of the next three vehicles inspected fail as follows:

P (At least 1 of 3 fails) = 1 - P (All 3 vehicles pass)

$=1-0.343\\=0.657$

Thus, the probability that at least 1 of the next three vehicles inspected fail is 0.657.

(c)

Compute the probability that exactly 1 of the next three vehicles passes as follows:

P (Exactly one) = P (1st vehicle or 2nd vehicle or 3 vehicle)

= P (Only 1st vehicle passes) + P (Only 2nd vehicle passes)

+ P (Only 3rd vehicle passes)

$=(0.70\times0.30\times0.30) + (0.30\times0.70\times0.30)+(0.30\times0.30\times0.70)\\=0.189$

Thus, the probability that exactly 1 of the next three vehicles passes is 0.189.

(d)

Compute the probability that at most 1 of the next three vehicles passes as follows:

P (At most 1 vehicle passes) = P (Exactly 1 vehicles passes)

+ P (0 vehicles passes)

$=0.189+(0.30\times0.30\times0.30)\\=0.216$

Thus, the probability that at most 1 of the next three vehicles passes is 0.216.

(e)

Let <em>X</em> = all 3 vehicle passes and <em>Y</em> = at least 1 vehicle passes.

Compute the conditional probability that all 3 vehicle passes given that at least 1 vehicle passes as follows:

$P(X|Y)=\frac{P(X\cap Y)}{P(Y)} =\frac{P(X)}{P(Y)} =\frac{(0.70)^{3}}{[1-(0.30)^{3}]} =0.3525$

Thus, the probability that all 3 vehicle passes given that at least 1 vehicle passes is 0.3525.

7 0

2 years ago

Graph the line that goes through the point (-6,-2) with slope of 1

vekshin1

Answer:

<h2>Check out the image.</h2>

Step-by-step explanation:

Let, the equation of the straight line is y = mx + c; where m is the slope of the equation and c is the constant.

The line has the slope 1.

Hence, the equation becomes y = x + c.

Since, the line passes through (-6, -2), -2 = -6 + c or, c = 4.

Hence, the equation of the straight line becomes y = x + 4.

Putting x = 0, we get, y = 4.

The line passes through (0, 4).

7 0

3 years ago

Simplify LaTeX: \Large\frac{-4^{6} \cdot 4^{2}}{4^{4}}

Oksanka [162]

⇨ The value of this <u>simplified expression</u> = -4096/1 or -4096.

To solve this expression, just multiply the power base by how many times indicate the exponent, and then divide the numerator and denominator of the fraction by the same number.

Power or potentiation is a multiplication in equal factors, where there are <em>terms responsible</em> for obtaining the final result. An potency is given by $\large \sf a^{n}.$ The terms of a power are:

Base
Exponent
equal factors
power

✏️ <u>Resolution/Answer</u>:

$\\ \large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=\\\\$

Multiply the powers of the numbers at numerator of the fraction, with the base <em>being multiplied by how many times</em> to indicate the exponent.

$\\\large \sf \dfrac{-4^{6} \cdot 4^{2}}{4^{4}}=$