Sorry I am a little late...
a = -2
b = -9
Here is how to solve the problem.
First thing I did was multiply the first equation by -2 so that we can eliminate the the b. After you multiply it by -2, your new equation is -16a + 8b = -40.
You leave the second equation alone and all you do is combine like terms. So -16a+5a is -11. And you eliminate the b. Then you're going to do -40+62 which is 22. So it's -11a=22 and then you have to solve for a. What I did was I multiplied the whole thing by minus to turn the a positive. So then it's 11a=-22. Pretty easy, the final step is to simplify. -22/11 is -2. ;D
So there you have your first answer.
a = -2
Now we're going to use the first answer to help us find b.
For the second equation, all you're going to do is plug in that a.
5 (-2)-8b=62
-10 - 8b = 62
Now we move the -10 to the other side...
-8b = 62 + 10
-8b = 72
Multiply the whole thing by negative once again to turn the b positive.
Now we have 8b = -72
The final step is to simplify. -72/11 = -9
b = -9
Hope this makes sense! Also I had the same question on my test and I got it right. :)
Answer:
Rectangle
Step-by-step explanation:
Answer:
Option 2: 27 is the correct answer.
Step-by-step explanation:
Given functions are:

As we can see that the function g(x) in written in terms of f(x), first of all we have to find g(x) by putting the value of f(x) in g(x)
So putting f(x) = x^2-2 in g(x)

As g(-3) has to be found, putting x=-3 in g(x)

Hence
Option 2: 27 is the correct answer.
Answer:
The given statement:
The expression cos^-1 (3/5) has an infinite number of values is a true statement.
Step-by-step explanation:
We are given a expression as:

Let us equate this expression to be equal to some angle theta(θ)
i.e.
Let

As we know that the limit point of the cosine function is [-1,1]
i.e. it takes the value between -1 to 1 and including them infinite number of times.
Also,
-1< 3/5 <1
This means that the cosine function takes this value infinite number of times.
That is there exist a infinite number of theta(θ) for which:

i.e. the expression:
has infinite number of values.