The length of segment AE is 5 centimeters. What is the length of segment CD?

Mathematics

1 answer:

kiruha [24]3 years ago

5 0

Is there a graph or diagram that goes with this question? If so then I can answer it if I’m able to see the picture

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Jenny spent 35 minutes doing research on the internet. She finished at 7:10 p.m. At what time did Jenny start her research?

drek231 [11]

She started at 6:35 p.m,
because minus 10 from the 7:10, you just have 7 now right? And she only has 25 min left. then minus 25 from 60 to get your answer. it is 6 35 pm.

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3 years ago

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Johns car averages 28 miles per gallon. how far can her drive on 8.25 gallons

Lilit [14]

Answer:

Step-by-step explanation:

This is a unit problem.

$\frac{28mpg}{8.25g}$

If you notice in that ratio, there is a "g" in both the numerator and the denominator which will cancel out, leaving you only with the label of miles, which is what you are looking for (since "how far can she drive..." is a distance thing). 28 then only needs to be divided by 8.25 to see how many miles this is.

$\frac{28mpg}{8.25g}=3.3939393939$ miles which, in an improper fraction, is

$\frac{112}{33}$ miles

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3 years ago

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Suppose integral subscript 3 superscript 5 f (x )space d x equals 5 integral subscript 3 superscript 9 g (x )space d x equals 3

igomit [66]

Answer:

Step-by-step explanation:

First we need to find the integral from 3 to 5 of g(x).

$\int\limits^9_3 {g(x)} \, dx =\int\limits^5_3 {g(x)} \, dx +\int\limits^9_5 {g(x)} \, dx \\\\\int\limits^5_3 {g(x)} \, dx =\int\limits^9_3 {g(x)} \, dx -\int\limits^9_5 {g(x)} \, dx\\\\\int\limits^5_3 {g(x)} \, dx =3-4=-1$

Then the integral of interest is ...

$\int\limits^5_3 {(f(x)+2g(x))} \, dx =\int\limits^5_3 {f(x)} \, dx +2\int\limits^5_3 {g(x)} \, dx =5+2(-1)\\\\\boxed{\int^5_3 {(f(x)+2g(x))} \, dx =3}$